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我正在从一个名为post的表中检索帖子。我想为此代码添加评论功能,问题是最新的帖子变量比其他人更具优势,因为如果您对较早的帖子发表评论,“最新帖子的变量(由于ORDER BY ID DECS标准” 有人帮我做这个职位无关自己...谢谢如何让mysql生成的帖子独立于自己
<?php
$sqlhash="SELECT * FROM posts ORDER BY id DESC ";
$result_hash = mysqli_query($conn,$sqlhash);
while($rowhash = mysqli_fetch_assoc($result_hash))
{
$user = $rowhash['user'];
$message = $rowhash['post'];
$time = $rowhash['time'];
$id= $rowhash['id'];
$tt = date('m/d/Y H:i:s',$time);
$my_id = $_SESSION['user_id'];
$sql="SELECT * FROM users WHERE Full_name='$user' ";
$result_set = mysqli_query($conn,$sql);
while($row = mysqli_fetch_assoc($result_set))
{
$select_username = $row['Full_name'];
$profp = $row['pic'];
$my_id = $_SESSION['user_id'];
?>
<center><div class='post' style='width:48%; height:40%; align:middle; text-align:left; margin:30px 0'>
<img width="70" height="70" src='uploads/<?php echo $profp; ?>'><br><p style='color:#0c88b5'><b> <?php echo $id ;?><br><?php echo $user ;?>On:<?php echo $tt ; ?><h4><b><?php echo $message
;?></h4></p><hr>
<?php
$sqlcom="SELECT * FROM comment WHERE hash='$id' ";
$result_com = mysqli_query($conn,$sqlcom);
while($rowcom = mysqli_fetch_assoc($result_com))
{
$usercom = $rowcom['comment'];
$comenter = $rowcom['user'];
echo "<p style='color:#0c88b5' $comenter</p>". ":" ;
echo $usercom. "<br>" ;
}
if (isset($_POST['commen'])) {
$sqlhash= "SELECT * FROM posts WHERE post= '$message' ";
$result_hash = mysqli_query($conn,$sqlhash);
while($rowhash = mysqli_fetch_assoc($result_hash))
{
$user1 = $_SESSION['username'];
$comment = $_POST['commen'];
$time = $rowhash['time'];
$time2 = $_SESSION['time'];
$sql3 = "INSERT INTO comment (user, comment, hash) VALUES
('$user1','$comment', '$id')";
if($conn->query($sql3) === TRUE) {
header('Location: timeline.php');
}else {
echo"error";
}
您是否正在维护帖子及其回复的结构线程? –
没有mayank。我简单地将它们保存到数据库中,然后在它们到来时检索它们...然后我想添加评论功能,但由于最后一篇文章过于强调其他内容,所以我无法对任何特定的文章发表评论..帮助我全部使这个系统更好的技术 –