Oracle中的枢轴关键字

Question

我可以使用Oracle中的PIVOT关键字通过使用单个查询而不是两个查询来创建多行的多个列，如下所示。 例如..

1）

SELECT 
    * 
FROM 
(
SELECT elig.person_id,elig.cmpo_key, recm.pyin_amt FROM sp_cmpo_elig elig, sp_base_pay_recm recm 
    WHERE elig.cmpo_elig_key=recm.cmpo_elig_key AND elig.person_id='807114') temp 
pivot (Max(temp.pyin_amt) FOR (cmpo_key) IN (1 AS pyin_amt_1, 2 AS pyin_amt_2, 3 AS pyin_amt_3, 4 AS pyin_amt_4)) 

如果使用此查询，我正在像下面的输出..

PERSON_ID PYIN_AMT_1 PYIN_AMT_2 PYIN_AMT_3 PYIN_AMT_4 
807114  1524.23  235.25 235.25  235.25 

2）

SELECT 
    * 
FROM 
(
SELECT elig.person_id,elig.cmpo_key, recm.pyin_pct FROM sp_cmpo_elig elig, sp_base_pay_recm recm 
    WHERE elig.cmpo_elig_key=recm.cmpo_elig_key AND elig.person_id='807114') temp 
pivot (Max(temp.pyin_pct) FOR (cmpo_key) IN (1 AS pyin_pct_1, 2 AS pyin_pct_2, 3 AS pyin_pct_3, 4 AS pyin_pct_4)) 

输出：

PERSON_ID PYIN_PCT_1 PYIN_PCT_2 PYIN_PCT_3 PYIN_PCT_4 
807114  2    5   5   3 

我可以如上创建单个查询而不是两个查询。请为此提供解决方案。

注：本人与工会也试过，如果我使用union它会给两个记录像下面...

PERSON_ID PYIN_AMT_1 PYIN_AMT_2 PYIN_AMT_3 PYIN_AMT_4 
807114  1524.23  235.25 235.25  235.25 
807114  2    5  5    3 

我期望的输出上面不喜欢的，我期待像下面....

PERSON_ID PYIN_AMT_1 PYIN_AMT_2 PYIN_AMT_3 PYIN_AMT_4 PYIN_PCT_1 PYIN_PCT_2 PYIN_PCT_3 PYIN_PCT_4 
807114  1524.23  235.25 235.25  235.25  2    5  5    3 

Answer 1

SELECT 
    * 
FROM 
(
SELECT elig.person_id,elig.cmpo_key, recm.pyin_amt FROM sp_cmpo_elig elig, sp_base_pay_recm recm 
    WHERE elig.cmpo_elig_key=recm.cmpo_elig_key AND elig.person_id='807114') temp 
pivot (Max(temp.pyin_amt) FOR (cmpo_key) IN (1 AS pyin_amt_1, 2 AS pyin_amt_2, 3 AS pyin_amt_3, 4 AS pyin_amt_4)) 
UNION 
SELECT 
    * 
FROM 
(
SELECT elig.person_id,elig.cmpo_key, recm.pyin_pct FROM sp_cmpo_elig elig, sp_base_pay_recm recm 
    WHERE elig.cmpo_elig_key=recm.cmpo_elig_key AND elig.person_id='807114') temp 
pivot (Max(temp.pyin_pct) FOR (cmpo_key) IN (1 AS pyin_pct_1, 2 AS pyin_pct_2, 3 AS pyin_pct_3, 4 AS pyin_pct_4))