如何在C++中将一个C＃结构转换为另一个？

Question

假设我们有两个C＃结构：

[Serializable, StructLayout(LayoutKind.Sequential, Pack = 1)] 
    public struct ByteStructure 
    { 
     public byte byte0; 
     public byte byte1; 
     public byte byte2; 
     public byte byte3; 
     public byte byte4; 
     public byte byte5; 
     public byte byte6; 
     public byte byte7; 
     public byte byte8; 
     public byte byte9; 
     public byte byteA; 
     public byte byteB; 
     public byte byteC; 
     public byte byteD; 
     public byte byteE; 
     public byte byteF; 
    } 

    [Serializable, StructLayout(LayoutKind.Sequential, Pack = 1)] 
    public struct IntStructure 
    { 
     public int i0; 
     public int i1; 
     public int i2; 
     public int i3; 
     } 

     ByteStructure bs; 
     IntStructure is; 
... 

如何在C++一个结构转换到另一个像：

is = (IntStructure)bs; 

或

bs = (ByteStructure)is; 

Answer 1

最简单的方法是使用Marshal类和非托管内存。

static void Main(string[] args) 
    { 
     ByteStructure b = new ByteStructure(); 
     IntStructure i = new IntStructure(); 
     i.i0 = 0xa; 
     i.i1 = 0xb; 
     i.i2 = 0xc; 
     i.i3 = 0xd; 

     Debug.Assert(Marshal.SizeOf(typeof(IntStructure)) == Marshal.SizeOf(typeof(ByteStructure))); 

     IntPtr mem = Marshal.AllocHGlobal(Marshal.SizeOf(typeof(IntStructure))); 
     Marshal.StructureToPtr(i, mem, false); 
     b = (ByteStructure)Marshal.PtrToStructure(mem, typeof(ByteStructure)); 
     Marshal.FreeHGlobal(mem); 

    }