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我已经设定这个至今:GoogleSignInApi了java.lang.RuntimeException:不提供结果ResultInfo {谁= NULL,请求= 9001,结果= -1,数据=意向{(有演员)}}
public void signIn() {
Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(googleclient);
startActivityForResult(signInIntent, RC_SIGN_IN);
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
// Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...);
if (requestCode == RC_SIGN_IN) {
if(resultCode == RESULT_OK){
GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
handleSignInResult(result);
}
}
}
private void handleSignInResult(GoogleSignInResult result) {
Log.d("TAG", "handleSignInResult:" + result.isSuccess());
if (result.isSuccess()) {
GoogleSignInAccount acct = result.getSignInAccount();
if(acct != null){
Log.d("oke", acct.getDisplayName());
}
} else {
}
}
这段代码给了我在标题中提到的错误。 我不知道为什么会发生这种情况,在我的其他项目中,一切正常。