快速谷歌搜索从Appache hadoop项目返回我this。从那里复制: (Apache许可证,版本2.0):
private static DecimalFormat oneDecimal = new DecimalFormat("0.0");
/**
* Given an integer, return a string that is in an approximate, but human
* readable format.
* It uses the bases 'k', 'm', and 'g' for 1024, 1024**2, and 1024**3.
* @param number the number to format
* @return a human readable form of the integer
*/
public static String humanReadableInt(long number) {
long absNumber = Math.abs(number);
double result = number;
String suffix = "";
if (absNumber < 1024) {
// nothing
} else if (absNumber < 1024 * 1024) {
result = number/1024.0;
suffix = "k";
} else if (absNumber < 1024 * 1024 * 1024) {
result = number/(1024.0 * 1024);
suffix = "m";
} else {
result = number/(1024.0 * 1024 * 1024);
suffix = "g";
}
return oneDecimal.format(result) + suffix;
}
它采用1K = 1024,但如果你喜欢,你可以适应这一点。您还需要使用不同的DecimalFormat处理< 1024个案例。
看到http://stackoverflow.com/问题/ 3758606 /如何将字节大小转换为人类可读格式的Java中更清洁的解决方案 – Niko 2013-06-18 07:01:16