拆分列表为单独列出[Python的]

Question

我有一个列表，说

listx = [1, 2, 0, 5, 2, 3, 0, 3, 4, 2, 3, 5, 6, 0, 4] 

你如何分割成清单不包含0连续的部分？例如，该列表将被分成

separated = [[1, 2], [5, 2, 3], [3, 4, 2, 3, 5, 6], [4]] 

Answer 1

import itertools 

In [69]: L = [1, 2, 0, 5, 2, 3, 0, 3, 4, 2, 3, 5, 6, 0, 4] 

In [70]: [list(i[1]) for i in itertools.groupby(L, bool) if i[0]] 
Out[70]: [[1, 2], [5, 2, 3], [3, 4, 2, 3, 5, 6], [4]] 

Answer 2

如果没有重复0's：

listx = [1, 2, 0, 5, 2, 3, 0, 3, 4, 2, 3, 5, 6, 0, 4] 

final = [[]] 
for ele in listx: 
    final[-1].append(ele) if ele else final.append([]) 

print(final) 
[[1, 2], [5, 2, 3], [3, 4, 2, 3, 5, 6], [4]] 

如果你重复0's：

def split_l(l): 
    final = [[]] 
    for ele in l: 
     final[-1].append(ele) if ele else final.append([]) 
    return filter(None, final) 

In [146]: timeit split_l(L) 
100 loops, best of 3: 19.6 ms per loop 

In [147]: timeit [list(i[1]) for i in itertools.groupby(L, bool) if i[0]] 
10 loops, best of 3: 33.8 ms per loop