如何排序从一个简单的SQL查询

Question

我的SQL

SELECT nce.id, nce.send, count(*) AS total 
FROM `newsletter_email` nce 
WHERE 1 
GROUP BY nce.id, nce.send 

结果产生的结果为：

id send total 
4 0  6 
4 1  1 
5 0  2 
6 1  7 
7 1  4 
8 0  2 
8 1  4 
9 1  1 

但我希望得到的结果是：

id send no_send  total 
4 6  1   7 
5 0  2   2 
6 7  0   7 
7 4  0   4 
8 4  2   6 
9 1  0   1 

我曾尝试几种方式，但它没有给出预期的结果。你能帮我吗？

Answer 1

假设发送有1对发送和0值no_send，你可以简单地总结发送的值：

SELECT nce.id, 
    sum(nce.send) as Send, 
    sum(1 - nce.send) as NO_send, 
    count(nce.send) as Total 
FROM `newsletter_email` nce 
GROUP BY nce.id 

然而，一般模式为：

SELECT nce.id, 
    sum(case when nce.send = 1 then 1 end) as Send, 
    sum(case when nce.send = 0 then 1 end) as NO_send, 
    count(nce.send) as Total 
FROM `newsletter_email` nce 
GROUP BY nce.id