我有点新使用JSON格式操作,并且在JAXB中也没有很好的实验。 我试图做的是建立一个小型客户端在Twitter上启动搜索。我的起始框架是JBoss RESTEasy(JAX-RS实现),它通过将JSON映射到JAXB并通过Jettison框架提供了一种优雅的方式来使用Rest服务JSON服务(如果您想提供REST服务并从中生成JSON, JAXB)。帮助映射JSON Twitter与Jetxison的Jaxb答案
所以我推出一个简单的请求到Twitter:
http://search.twitter.com/search.json?q=java
而且答案来自于以下JSON格式
{
"results":
[
{"from_user_id_str":"67875385",
"profile_image_url":"http://a2.twimg.com/axt_normal.png",
"created_at":"Sun, 28 Nov 2010 22:38:39 +0000",
"from_user":"extant",
"id_str":"9013327095136256",
"metadata":{"result_type":"recent"},
"to_user_id":null,
"text": "New blog post: No fancy swap in java",
"id":9013327095136256,
"from_user_id":67875385,
"geo":null,
"iso_language_code":"en",
"to_user_id_str":null,
"source":"wordpress"
},
<more tweets...>
],
"max_id":9013327095136256,
"since_id":0,
"refresh_url":"?since_id=9013327095136256&q=java",
"next_page":"?page=2&max_id=9013327095136256&q=java",
"results_per_page":15,
"page":1,"completed_in":0.020154,
"since_id_str":"0",
"max_id_str":"9013327095136256",
"query":"java"
}
所以我创建了两个类来映射这个答案
@BadgerFish
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class SearchResults {
@XmlElement
public List<Tweet> results;
@XmlElement(name = "max_id")
public long maxId;
@XmlElement(name = "since_id")
public long sinceId;
}
and
@BadgerFish
@XmlRootElement(name="tweet")
public class Tweet {
@XmlElement(name = "id")
public long id;
@XmlElement(name = "text")
public String text;
@XmlElement(name = "created_at")
public Date createdAt;
@XmlElement(name = "from_user")
public String fromUser;
@XmlElement(name = "profile_image_url")
public String profileImageUrl;
@XmlElement(name = "to_user_id")
public Long toUserId;
@XmlElement(name = "from_user_id")
public long fromUserId;
@XmlElement(name = "language_code")
public String languageCode;
@XmlElement(name = "source")
public String source;
}
我的Twitter的RESTEasy客户端是一个简单的接口
public interface TwitterResource {
@Path("/search.json")
@Consumes("application/*+json")
@GET
SearchResults search(@QueryParam("q")String query);
}
这与下面的RESTEasy代码开发:
...
TwitterResource tr = ProxyFactory.create(TwitterResource.class, "http://search.twitter.com");
SearchResults sr = tr.search("java");
...
此代码给出以下异常:
Exception in thread "main" org.jboss.resteasy.plugins.providers.jaxb.JAXBUnmarshalException: javax.xml.bind.JAXBException
- with linked exception:
[org.codehaus.jettison.json.JSONException: JSONObject["results"] is not a JSONObject.]
at org.jboss.resteasy.plugins.providers.jaxb.AbstractJAXBProvider.readFrom(AbstractJAXBProvider.java:86)
我假设它来自SearchResults类上错误的JAXB映射,但无法确定如何更正等它(它与JSON翻译到XML复杂)。任何改正它的线索都会很棒。
在此先感谢
下面是如何可以用的EclipseLink JAXB(莫西)来完成一个完整的例子:http://blog.bdoughan.com/2011/08/json-binding-with- eclipselink-moxy.html – 2012-06-29 20:03:08