如何总结xsl中每个类别的值？

Question

我需要总结通过我们的合作伙伴XML地点销售（不知道有多少提前位置）：

样本输入：

<company> 
    <deparment dept="001"> 
     <location> 
      <locationCode>001</locationCode> 
      <sales>10000</sales> 
     </location> 
     <location> 
      <locationCode>0005</locationCode> 
      <sales>12500</sales> 
     </location> 
    </deparment> 
    <deparment dept="002"> 
     <location> 
      <locationCode>001</locationCode> 
      <sales>40000</sales> 
     </location> 
     <location> 
      <locationCode>004</locationCode> 
      <sales>30000</sales> 
     </location> 
    </deparment> 
    <deparment dept="003"> 
     <location> 
      <locationCode>004</locationCode> 
      <sales>60000</sales> 
     </location> 
    </deparment> 
</company> 

预期的输出：

<location> 
    <locationCode>001</locationCode> 
    <totalSales>50000</locationCode> 
<location> 
<location> 
    <locationCode>005</locationCode> 
    <totalSales>12500</locationCode> 
<location> 
<location> 
    <locationCode>004</locationCode> 
    <totalSales>90000</locationCode> 
<location> 

不xsl有类似于group-by的内容吗？我是xsl的新手，并感谢任何帮助。

谢谢。

Answer 1

我知道它为xslt 1.0工作。

<xsl:key name="Location" match="/company/deparment/location" use="locationCode"/> 

<xsl:template match="company"> 
    <company> 
    <xsl:for-each select="./deparment/location[generate-id() = generate-id(key('Location', ./locationCode)[1])]"> 
    <xsl:variable name="LocationCode" select="./locationCode"/> 
    <location> 
     <locationCode> 
     <xsl:value-of select="$LocationCode"/> 
     </locationCode> 
     <totalSales> 
     <xsl:value-of select="sum(//location[locationCode = $LocationCode]/sales)"/> 
     </totalSales> 
    </location> 
    </xsl:for-each> 
    </company> 
</xsl:template> 

请查看muenchian method以了解将来的问题。

Answer 2

对于XSLT 2.0（与的xsl：for-各个群组指令）：

<xsl:stylesheet 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    version="2.0" > 

    <xsl:output indent="yes" /> 

    <xsl:template match="/"> 
     <xsl:for-each-group select="company/deparment/location" group-by="locationCode"> 
      <location> 
       <locationCode><xsl:value-of select="current-grouping-key()"/></locationCode> 
       <totalSales><xsl:value-of select="sum(current-group()/sales)"/></totalSales> 
      </location> 
     </xsl:for-each-group> 

    </xsl:template> 

</xsl:stylesheet> 

Answer 3

这将是使用XSLT 2.0的溶液：

对于以下输入XML：

<?xml version="1.0" encoding="UTF-8"?> 
<company> 
    <department dept="001"> 
     <location> 
      <locationCode>001</locationCode> 
      <sales>10000</sales> 
     </location> 
     <location> 
      <locationCode>0005</locationCode> 
      <sales>12500</sales> 
     </location> 
    </department> 
    <department dept="002"> 
     <location> 
      <locationCode>001</locationCode> 
      <sales>40000</sales> 
     </location> 
     <location> 
      <locationCode>004</locationCode> 
      <sales>30000</sales> 
     </location> 
    </department> 
    <department dept="003"> 
     <location> 
      <locationCode>004</locationCode> 
      <sales>60000</sales> 
     </location> 
    </department> 
</company> 

使用以下XSLT：

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output indent="yes" /> 
<xsl:template match="/company"> 
<company> 
    <xsl:for-each-group select="department/location" group-by="locationCode"> 
     <location> 
      <locationCode><xsl:value-of select="current-grouping-key()"/></locationCode> 
      <totalSales><xsl:value-of select="sum(current-group()/sales)"/></totalSales> 
     </location> 
    </xsl:for-each-group> 
</company> 
</xsl:template> 
</xsl:stylesheet> 

我得到的输出：

<?xml version="1.0" encoding="UTF-8"?> 
<company xmlns:xs="http://www.w3.org/2001/XMLSchema"> 
    <location> 
     <locationCode>001</locationCode> 
     <totalSales>50000</totalSales> 
    </location> 
    <location> 
     <locationCode>0005</locationCode> 
     <totalSales>12500</totalSales> 
    </location> 
    <location> 
     <locationCode>004</locationCode> 
     <totalSales>90000</totalSales> 
    </location> 
</company> 

Answer 4

短，简单和有效的XSLT 1.0溶液（没有变量，没有xsl:for-each）：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output omit-xml-declaration="yes" indent="yes"/> 

<xsl:key name="kLocById" match="location" use="locationCode"/> 

<xsl:template match= 
    "location 
    [generate-id() 
    = 
    generate-id(key('kLocById',locationCode)[1]) 
    ]"> 
    <location> 
    <xsl:copy-of select="locationCode"/> 
    <totalSales> 
    <xsl:value-of select="sum(key('kLocById',locationCode)/sales)"/> 
    </totalSales> 
    </location> 
</xsl:template> 
<xsl:template match="text()"/> 
</xsl:stylesheet> 

当这种转化应用于提供的XML文档：

<company> 
    <deparment dept="001"> 
     <location> 
      <locationCode>001</locationCode> 
      <sales>10000</sales> 
     </location> 
     <location> 
      <locationCode>0005</locationCode> 
      <sales>12500</sales> 
     </location> 
    </deparment> 
    <deparment dept="002"> 
     <location> 
      <locationCode>001</locationCode> 
      <sales>40000</sales> 
     </location> 
     <location> 
      <locationCode>004</locationCode> 
      <sales>30000</sales> 
     </location> 
    </deparment> 
    <deparment dept="003"> 
     <location> 
      <locationCode>004</locationCode> 
      <sales>60000</sales> 
     </location> 
    </deparment> 
</company> 

的希望，正确的结果产生：

<location> 
    <locationCode>001</locationCode> 
    <totalSales>50000</totalSales> 
</location> 
<location> 
    <locationCode>0005</locationCode> 
    <totalSales>12500</totalSales> 
</location> 
<location> 
    <locationCode>004</locationCode> 
    <totalSales>90000</totalSales> 
</location> 

说明：适当使用Muenchian method for grouping和模板匹配的。