为什么在统一中我得到警告：您正试图使用​​'new'关键字创建MonoBehaviour？

Question

完整的警告信息：

您正试图使用​​'new'关键字创建MonoBehaviour。这是不允许的。 MonoBehaviours只能使用AddComponent（）添加。或者，你的脚本就可以在所有

从个ScriptableObject或没有基类继承，在这两个脚本我不使用“新”的关键字：

的DetectPlayer脚本：

using UnityEngine; 
using System.Collections; 
using System.Reflection; 

public class DetectPlayer : MonoBehaviour { 

    GameObject target; 
    int counter = 0; 

    void OnCollisionEnter(Collision collision) 
    { 
     if (collision.gameObject.name == "Platform") 
     { 
      Debug.Log("Touching Platform"); 
      //GameObject findGo = GameObject.Find("ThirdPersonController"); 
      //findGo.transform.parent = null; 
     }   
    } 

    void OnTriggerEnter(Collider other) 
    { 
     if (other.gameObject.name == "OnTop Detector") 
     { 
      counter = 0; 
      Debug.Log("On Top of Platform"); 
      target = GameObject.Find("Elevator"); 
      GameObject findGo = GameObject.Find("ThirdPersonController"); 
      GameObject findGo1 = GameObject.Find("Elevator"); 
      findGo.transform.parent = findGo1.transform; 
      StartCoroutine(playAnim(target)); 
     } 
    } 

    void OnTriggerExit(Collider other) 
    { 
     GameObject findGo = GameObject.Find("ThirdPersonController"); 
     findGo.transform.parent = null; 
    } 

    IEnumerator playAnim(GameObject target) 
    { 
     Animation anim = target.GetComponent<Animation>(); 

     foreach (AnimationState clip in anim) 
     { 
      // do initialisation or something on clip 
      clip.speed = 1; 
     } 

     while (true) 
     { 
      if (counter == 1) 
       break; 
      //Play Up Anim 
      anim.Play("Up"); 

      //Wait until Up is done Playing the play down 
      while (anim.IsPlaying("Up")) 
      { 
       yield return null; 
      } 

      //Now Play Down Anim 
      anim.Play("Down"); 

      //Wait until down is done Playing 
      while (anim.IsPlaying("Down")) 
      { 
       yield return null; 
      } 

      yield return null; //Make sure there is no freezing 

      //Return to the top of the while|true loop 

      counter++; 
     } 
    } 

    void OnGUI() 
    { 
     GUI.Box(new Rect(300, 300, 200, 20), 
      "Times lift moved up and down " + counter); 
    } 
} 

电梯脚本：

using UnityEngine; 
using System.Collections; 

public class Lift : MonoBehaviour { 

    private bool pressedButton = false; 
    private bool isElevatorUp = false; 

    GameObject target; 

    DetectPlayer dp = new DetectPlayer(); 

    void OnMouseOver() 
    { 
     pressedButton = true; 
    } 

    void OnMouseExit() 
    { 
     pressedButton = false; 
    } 

    void OnMouseDown() 
    { 
     if(isElevatorUp == false) 
     { 
      target = GameObject.Find("Elevator"); 
      target.GetComponent<Animation>().Play("Up"); 
      isElevatorUp = true; 
     } 
     else 
     { 
      target = GameObject.Find("Elevator"); 
      target.GetComponent<Animation>().Play("Down"); 
      isElevatorUp = false; 
     } 
    } 

    void OnGUI() 
    { 
     if(pressedButton == true) 
     { 
      GUI.Box(new Rect(300, 300, 200, 20), "Press to use lift!"); 
     } 
    } 
} 

Answer 1

最好不要将MonoBehaviours看作传统意义上的C＃对象。他们应该被认为是自己独特的东西。它们在技术上是Unity基于的实体组件系统体系结构的“组件”部分。

因此，一个MonoBehaviour是一个Component，它不能存在于一个GameObject上。因此，仅用'新'关键字创建MonoBehaviour不起作用。要创建MonoBehaviour，你必须在GameObject上使用AddComponent。

此外，您不能在类作用域创建一个新的GameObject。一旦游戏运行，它必须以一种方法完成，一个理想的地方是在醒来。

你想要做什么是

DetectPlayer dp; 

    void Awake() 
    { 
     GameObject gameObject = new GameObject("DetectPlayer"); 
     dp = gameObject.AddComponent<DetectPlayer>(); 
    }