如何根据Group BY列对两个查询的结果进行求和？

我有一个足球比赛中所有历史比赛的比赛表。它大约有30000场比赛，我的挑战是为特定队伍和其他队伍找回胜利，平局和失败。如何根据Group BY列对两个查询的结果进行求和？

对于我的问题我就用画，为了找回我的画我有2种可能的方案：

球队是主队
队是客场团队

所以根据我的数据的查询在我的队是主队的第一个场景是这样的：

SELECT 
    matches.away_team as VS, 
    COUNT(matches.idmatch) AS TIES 
FROM 
    my_football_database.matches 
WHERE 
    home_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
GROUP BY 
    away_team 
LIMIT 5;

输出：

+------+------+ 
| VS | TIES | 
+------+------+ 
| 2 | 1 | 
| 3 | 3 | 
| 4 | 2 | 
| 8 | 1 | 
| 9 | 3 | 
+------+------+

第二种情况是，当我的球队是客队，所以它是这样的：

SELECT 
    matches.home_team as VS, 
    COUNT(matches.idmatch) AS TIES 
FROM 
    my_football_database.matches 
WHERE 
    away_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
GROUP BY 
    home_team 
LIMIT 5;

输出：

+------+------+ 
| VS | TIES | 
+------+------+ 
| 2 | 4 | 
| 3 | 2 | 
| 7 | 1 | 
| 8 | 3 | 
| 9 | 1 | 
+------+------+

由于你可以看到一个例子：

当我的团队（ID = 14）被打的主队VS团队ID = 3，共3场比赛的结束为平局
在第二个结果是，当我的球队（ID = 14）是作为客场对阵球队ID = 3，总共2场比赛结束为平局

如何根据“VS”ID结果TIES的结果？比如，在列出作为主队参赛的球队的所有关系之后，根据客队分组，并列出作为客队参赛队的所有关系，由主队归类，根据“Vs”ID加入两列。

的示例结果在这种情况下将是：

+------+------+ 
| VS | TIES | 
+------+------+ 
| 2 | 5 | 
| 3 | 5 | 
| 4 | 2 | 
| 7 | 1 | 
| 8 | 4 | 
| 9 | 4 | 
+------+------+

注：我得去找一个单一的查询，可以给我一个表的所有胜点，丢失，并绘制了给予球队，他们与他们对阵的球队分组。

这是14个总的情况。主场和客场抽签（2），主客场胜利，获奖并受到处罚（6）。主场和客场失去常规，获奖和罚球（6）。

因此，我并不是在寻找可能解决Draws交易的一段代码，而更像是一个关于如何研究，研究或实施这个问题的提示。我的第一个想法是分别创建每个场景，然后将它们用作子查询，但我被告知这对性能不方便。

来源

2017-04-13 Matias Diez

我无法理解你的描述。你能展示一个期望结果的样本吗？ – Barmar

我刚加了一个，试图解释得更好。谢谢！ –

使用CASE结构：

select 
    otherteam, 
    count(case when mygoals > othergoals then 1 end) as won, 
    count(case when mygoals = othergoals then 1 end) as ties, 
    count(case when mygoals < othergoals then 1 end) as lost 
from 
(
    select 
    11 as myteam, 
    case when home_team = 11 then away_team else home_team end as otherteam, 
    case when home_team = 11 then home_team_goals else away_team_goals end as mygoals, 
    case when home_team = 11 then away_team_goals else home_team_goals end as othergoals 
    from mydb.matches 
    where (home_team = 11 or away_team = 11) 
) whoiswho 
group by otherteam;

（哎呀，对不起，我想这是不是 “像HINT” 略多。）

来源

2017-04-13 22:09:25

这有点解决了一切，天才。虽然我会坐下来研究你的案例结构。谢谢！ –

使用两个查询中的UNION，然后将这些行与同一个VS列相加。

SELECT VS, SUM(TIES) AS TIES 
FROM (
    (SELECT matches.away_team as VS, count(matches.idmatch) as TIES 
    from my_football_database.matches WHERE home_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
    GROUP BY away_team 
    LIMIT 5) 
    UNION ALL 
    (SELECT matches.home_team as VS, count(matches.idmatch) as TIES 
    from my_football_database.matches WHERE away_team = 14 
    AND home_team_goals = away_team_goals 
    AND aet = "N" AND PK = "N" 
    GROUP BY home_team 
    LIMIT 5)) AS u 
GROUP BY VS

来源

2017-04-13 22:08:16 Barmar

如何根据Group BY列对两个查询的结果进行求和？

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