json返回[对象对象]提交点击

Question

我正在通过形式细节从离子到php文件throuugh控制器。如果我通过邮递员直接输入表格数据，它将被存储。但是，当我尝试通过填写表单数据，我得到这个错误：

每当我点击提交按钮，我得到这个错误提示框.- [目标对象]

I have also added the header in php but still am getting the error and alert box shows null. The data to be returned shows null all the time. I am not able to figure out the problem. Please help!!! 

这里是我的在那里我加入了访问控制PHP代码允许头

<?php 
header("Access-Control-Allow-Origin: *"); 
header('Access-Control-Allow-Headers: Origin, X-Requested-With, Content-Type, Accept'); 

require_once 'db_functions.php'; 
$db = new db_functions(); 
// json response array 
$response = array("error" => FALSE); 

if (isset($_POST['name']) && isset($_POST['email']) && isset($_POST['contact']) && isset($_POST['gender']) && isset($_POST['user_name']) && isset($_POST['password'])) 
{ 

if(is_numeric($_POST['name']) && is_numeric($_POST['gender'])) 
{ 
$response["status"] = false; 
$response["error_msg"] = "Name and gender cannot have numeric values"; 
echo json_encode($response); 
} 
if(!filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) 
{ 
$response["status"] = false; 
$response["error_msg"] = "Enter a valid email id"; 
echo json_encode($response); 
} 
else 
{ 

// receiving the GET params 
$name = $_POST['name']; 
$email = $_POST['email']; 
$password = $_POST['password']; 
$contact = $_POST['contact']; 
$gender = $_POST['gender']; 
$user_name = $_POST['user_name']; 
// check if user is already existed with the same email 
if ($db->isUserExisted($user_name)) { 
// user already existed 
$response["error"] = false; 
$response["error_msg"] = "User already existed with " . $user_name; 
echo json_encode($response); 
} 
else if ($db->isUserEmailExisted($email)) { 
// user already existed 
$response["error"] = false; 
$response["error_msg"] = "User already existed with " . $email; 
echo json_encode($response); 
} 
else if ($db->isUserContactExisted($contact)) { 
// user already existed 
$response["error"] = false; 
$response["error_msg"] = "User already existed with " . $contact; 
echo json_encode($response); 
} 
else { 
// create a new user 
$user = $db->storeUser($name, $email,$contact,$gender,$user_name,$password); 
if ($user) { 
// user stored successfully 
$response["error"] = true; 
$response["user"]["name"] = $user["name"]; 
$response["user"]["email"] = $user["email"]; 
$response["user"]["contact"] = $user["contact"]; 
$response["user"]["gender"] = $user["gender"]; 
$response["user"]["user_name"] = $user["user_name"]; 
$response["user"]["encrypted_password"] = $user["encrypted_password"]; 
$response["user"]["created_at"] = $user["created_at"]; 
$response["user"]["updated_at"] = $user["updated_at"]; 
echo json_encode($user); 
} else { 
// user failed to store 
$response["error"] = false; 
$response["error_msg"] = "Unknown error occurred in registration!"; 
echo json_encode($response); 
} 
} 
} 
} else { 
$response["error"] = false; 
$response["error_msg"] = "Required parameters are missing!"; 
echo json_encode($response); 
} 
?> 

这是我的控制器代码

angular.module('app.controllers', []) 

.controller('loginCtrl', function($scope) { 

}) 

.controller('selectYourRoleCtrl', function($scope) { 

}) 

.controller('userDetailsCtrl', function($scope,$http) { 
$scope.users = {}; 
$scope.users.gender = "Male"; 
$scope.regUser = function(){ 
$http.post("http://localhost/drmedic/register_user.php",$scope.users) 
.success(function(data){ 
alert(data); 
}) 
.error(function(data){ 
alert(data); 
}); 
} 
}) 

.controller('doctorDetailsCtrl', function($scope) { 

}) 

Answer 1

提醒对象只返回'对象对象'

var bla = { 
    'la1': 'la', 
    'la2': 'la' 
}; 
alert(bla); 

返回“对象对象”。如果你转向。

var bla = { 
    'la1': 'la', 
    'la2': 'la' 
}; 
alert(bla['la1']); 

返回“la”。 如果你需要你可以做。

var string = ''; 
var bla = { 
    'la1': 'la1', 
    'la2': 'la2' 
}; 
for (var i = 1; i <= 2; i++) { 
    string += bla['la'+i]; 
} 
alert(string); 

这将返回la1la2