我目前有以下代码,它从网页获取表格,并将元素放入HashMap(我认为)。从Java中的HashMap获取元素?
Document doc = Jsoup.connect(
"http://www.sportinglife.com/greyhounds/abc-guide").get();
Element tableHeader = doc.select("tbody").first();
Map<String, String> data = new HashMap<>();
for (Element element : tableHeader.children()) {
// Here you can do something with each element
if (element.text().indexOf("Pelaw Grange") > 0
|| element.text().indexOf("Shawfield") > 0
|| element.text().indexOf("Shelbourne Park") > 0
|| element.text().indexOf("Harolds Cross") > 0) {
// do nothing
} else {
String dog = element.select("td:eq(0)").text();
String race = element.select("td:eq(1)").text();
data.put(dog, race);
}
}
analyseRunners(data);
}
这似乎是工作确定,我现在需要它来运行其他方法“analyseRunners”,它需要经过每一个狗和使用“狗”的名称来访问其他网页那里是另一表。这里是我迄今为止...
String dogPage = "http://www.gbgb.org.uk/raceCard.aspx?dogName=" + dog;
Document doc1 = Jsoup.connect(dogPage).get();
int firsts = 0, seconds = 0, thirds = 0;
Element tblHeader = doc1.select("tbody").first();
for (Element element1 : tblHeader.children()){
String position = element1.select("td:eq(4)").text();
if (position.equals("1st")){
firsts++;
} else if (position.equals("2nd")){
seconds++;
} else if (position.equals("3rd")){
thirds++;
} else {
//do nothing
}
}
System.out.println("Firsts: " + firsts);
System.out.println("Seconds: " + seconds);
System.out.println("Thirds: " + thirds);
正如你所看到的,我试图导航到使用从上面的第一种方法“狗”在jSoup网页...这是不工作的它说“狗”不能解决。我如何才能从HashMap中获取狗的名字并循环遍历每只狗来计算出它有多少个1st,2nd和3rds? (此页面上的第五列:http://www.gbgb.org.uk/raceCard.aspx?dogName=A%20Real%20Legend)
'为(字符串狗:data.keySet()){//用狗}' – 2014-10-18 11:17:01