SQL SELECT语句与HAVING和OR

Question

我有一个表中有一些用户在里面。他们都有一个用户名，纬度，经度和其他一些领域。

我想选择给定坐标的5KM范围内的所有用户，并基于其他一些标准。现在这部分并不难。

但是，我也希望SQL语句能够返回给定用户名的用户，与上面提到的其他标准无关。

因此，基本上，SQL应基于距离和其他标准以及具有特定用户名的用户返回用户，尽管它们与条件匹配或不匹配。

这里是我有什么，但它不工作：

SELECT idUser 
    , username 
    , telephone 
    , latitude 
    , longitude 
    , (6371 * acos(cos(radians(?)) * cos(radians(latitude)) * cos(radians(longitude) - radians(?)) + sin(radians(?)) * sin(radians(latitude)))) AS distance 
    FROM main 
WHERE active = ? 
    AND idUser != ? 
HAVING distance < 5 
    OR username = mike 
    OR username = john 

Answer 1

您可以将条件添加到having条款：

SELECT idUser, username, telephone, latitude, longitude, 
     (6371 * acos(cos(radians(?)) * cos(radians(latitude)) * cos(radians(longitude) - radians(?)) + sin(radians(?)) * sin(radians(latitude)))) AS distance 
FROM main 
WHERE active = ? AND idUser != ? 
HAVING distance < 5 OR username IN ('mike', 'john'); 

您可能需要删除idUser。 。 。我不确定这是否与username有关。

编辑：

如果你想保证迈克和约翰是一个结果集，你可以这样做：

(SELECT idUser, username, telephone, latitude, longitude, 
     (6371 * acos(cos(radians(?)) * cos(radians(latitude)) * cos(radians(longitude) - radians(?)) + sin(radians(?)) * sin(radians(latitude)))) AS distance 
FROM main 
WHERE active = ? AND idUser != ? AND username NOT IN ('mike', 'john') 
HAVING distance < 5 
) 
UNION ALL 
(SELECT idUser, username, telephone, latitude, longitude, 
     (6371 * acos(cos(radians(?)) * cos(radians(latitude)) * cos(radians(longitude) - radians(?)) + sin(radians(?)) * sin(radians(latitude)))) AS distance 
FROM main 
WHERE username IN ('mike', 'john') 
) 

或者：

SELECT idUser, username, telephone, latitude, longitude, 
     (6371 * acos(cos(radians(?)) * cos(radians(latitude)) * cos(radians(longitude) - radians(?)) + sin(radians(?)) * sin(radians(latitude)))) AS distance 
FROM main 
WHERE (active = ? AND idUser <> ?) OR username IN ('mike', 'john') 
HAVING distance < 5 OR username IN ('mike', 'john'); 

或移动到所有条件HAVING子句：

SELECT idUser, username, telephone, latitude, longitude, 
     (6371 * acos(cos(radians(?)) * cos(radians(latitude)) * cos(radians(longitude) - radians(?)) + sin(radians(?)) * sin(radians(latitude)))) AS distance 
FROM main 
WHERE (active = ? AND idUser <> ?) OR username IN ('mike', 'john') 
HAVING (active = ? AND idUser <> ? AND distance < 5) OR 
     username IN ('mike', 'john');