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我在使用INNER JOIN查询时遇到问题。MYSQL加入条件可能为空
我有两个表。我需要部门名称和所有三个批准者。如果任何审批者都是NULL,我也需要显示。
mysql> desc department;
+-------------------+----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------------+----------+------+-----+---------+----------------+
| id | int(8) | NO | PRI | NULL | auto_increment |
| departmentName | tinytext | YES | | NULL | |
| primaryApprover | int(8) | YES | | NULL | |
| secondaryApprover | int(8) | YES | | NULL | |
| tertiaryApprover | int(8) | YES | | NULL | |
+-------------------+----------+------+-----+---------+----------------+
mysql> desc approver;
+------------------+------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------------+------------+------+-----+---------+----------------+
| id | int(8) | NO | PRI | NULL | auto_increment |
| approverName | tinytext | YES | | NULL | |
| approverPosition | tinytext | YES | | NULL | |
| approverLogonId | tinytext | YES | | NULL | |
| approverEmail | tinytext | YES | | NULL | |
| isActive | tinyint(1) | YES | | NULL | |
+------------------+------------+------+-----+---------+----------------+
下面的查询工作,但它并没有给我数据,其中一次或二次审批是NULL:
SELECT
a.departmentName as DEPARTMENT,
pa.approvername as PRIMARY,
sa.approvername as SECONDARY,
ta.approvername as TERTIARY
FROM
department as a
INNER JOIN
approver pa on a.primaryapprover=pa.id
INNER JOIN
approver sa on a.secondaryapprover = sa.id
INNER JOIN
approver ta on a.tertiaryapprover = ta.id
ORDER BY
a.departmentname;
使用此查询,我得到这样的结果:
+--------------------------------+---------------------------+---------------------------+------------------------+
| DEPARTMENT | PRIMARY_APPROVER | SECONDARY_APPROVER | TERTIARY_APPROVER |
+--------------------------------+---------------------------+---------------------------+------------------------+
| Facilities | Washburn, Hoban | Cobb, Jayne | Reynolds, Malcomn |
| Personnel/HR | Frye, Kaylee | Serra, Inara | Book, Dariel |
+--------------------------------+---------------------------+---------------------------+------------------------+
2 rows in set (0.00 sec)
但应该得到这个结果:
+--------------------------------+---------------------------+---------------------------+------------------------+
| DEPARTMENT | PRIMARY_APPROVER | SECONDARY_APPROVER | TERTIARY_APPROVER |
+--------------------------------+---------------------------+---------------------------+------------------------+
| Business Office | NULL | Rample, Fanty | Niska, Adelei |
| Facilities | Washburn, Hoban | Cobb, Jayne | Reynolds, Malcomn |
| Personnel/HR | Frye, Kaylee | Serra, Inara | Book, Dariel |
| Technical Services | Tam, River | NULL | Tam, Simon |
+--------------------------------+---------------------------+---------------------------+------------------------+
4 rows in set (0.00 sec)
我不擅长连接......我在这里错过了什么?
看起来你可以尝试用'LEFT JOIN'替换所有'INNER JOIN'。这不会消除连接表中具有空值的行。 –