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我试图在pyplot中添加一个按钮到我的窗口,没有像matplotlib.widgets文档中给出的例子,我不能发布漏洞代码(限制SO),但我认为问题是头无法将按钮添加到pyplot?
import matplotlib
import numpy as np
matplotlib.use('TkAgg')
from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg, NavigationToolbar2TkAgg
import matplotlib.pyplot as plt
from matplotlib.widgets import Slider, RadioButtons, Button
import time
import random
import sys
from tkinter import *
import matplotlib.animation as animation
import matplotlib.pyplot as plt
,按钮被实例化这样的:
class Index(object):
ind = 0
def next(self, event):
self.ind += 1
print("just pressed next")
callback = Index()
axprev = plt.axes([0.7, 0.05, 0.1, 0.075])
axnext = plt.axes([0.81, 0.05, 0.1, 0.075])
bnext = Button(axnext, 'Next')
bnext.on_clicked(callback.next)
bprev = Button(axprev, 'Previous')
bprev.on_clicked(callback.next)
当我运行代码,我得到以下错误:
我会试一试并回复你(我认为你是对的) –
像预期的那样,简单的错误。谢谢。在6分钟之前不能接受答案,稍后我会接受。 –