用Oracle SQL替换功能

Question

我使用Oracle SQL，和我有以下查询：

select replace(replace('count(distinct <thiscol>) over (partition by <nextcol>)/count(*) over() as <thiscol>_<nextcol>,', 
         '<thiscol>', column_name 
        ), '<nextcol>', lead(column_name) over (order by column_id) 
      ) 
from all_tab_columns atc 
where table_name = 'mytable' 

应该是查询，如按照输出：

select id, 
     count(distinct name2) over (partition by name3)/count(*) over(), 
     count(distinct name3) over (partition by name4)/count(*) over(), 
     . . . 
from mytable; 

我期待得到的，而不是：

count(distinct name2) over (partition by name3)/count(*) over() 

此查询：

count(distinct name3) over (partition by name2)/count(*) over() 

任何人都可以建议如何替换列值的顺序？ （<thiscol>和<nextcol>）。我试图用<nextcol>替换<thiscol>，但它给了我相同的结果。我尝试了很多成功的事情。

有人吗？

Answer 1

那就是真的很奇怪。相反，让我们按相反顺序排序：

select replace(replace('count(distinct <thiscol>) over (partition by <nextcol>)/count(*) over() as <thiscol>_<nextcol>,', 
         '<thiscol>', column_name 
        ), '<nextcol>', lead(column_name) over (order by column_id desc) 
      ) 
from all_tab_columns atc 
where table_name = 'mytable'; 

请注意desc的排序。