我想创建一个算法,但不知道如何开始。及时准确的连续数据算法
该算法实际上是一个接受具有一些属性createdAt值的N个对象的数组的方法。 我会将数组从旧到新排序(createdAt),然后我必须找出可用数据的一致性,也就是说,每隔一小时我至少有5条记录,并且每半小时记录两条记录。
例-testcode:
- (void) normalizeData:(NSArray*)records
{
// sort the records
NSArray* sortedRecords = [records sortWithCreatedAt];
// split all dates in the records, distinct them, and create a dictionary with a key for every date, for value create another dictionary with the hour as key and the records as the value.
NSArray* distinctDates = [sortedRecords valueForKeyPath:@"@distinctUnionOfObjects.createdAt"]; // should only consider month-day-year-hour
NSMutableDictionary* dictionary = [NSMutableDictionary dictionary];
for (NSDate* date in distinctDates)
{
NSString* stringDate = [date string];
NSArray* recordsForDate = [sortedRecords valueForKeyPath:[NSString stringWithFormat:@"[collect].{createdAt=%@}.self", stringDate]]; // let's say you got them with this line
[dictionary setObject:recordsForDate forKey:date];
}
for (NSDate* keyDate in dictionary)
{
NSArray* records = [dictionary objectForKey:keyDate];
Record* previousRecord = nil;
for (Records* record in records)
{
// I'll have to keep the previous record and compare the time difference with the new
NSInteger secondsAfterDate = 0;
if (previousRecord)
{
secondsAfterDate = [record.createdAt timeIntervalSinceDate:previousRecord.createdAt];
// add logic to create trend difference in a model that has for every hour of the records count, the records and suffice description
// logic if the records count and timespan is suffice.
}
previousRecord = record;
}
}
}
我希望在该方法的过程中的任何贡献。
此外,最终目标是为处理的记录的每个结果创建一个返回(调用块处理程序)。 逻辑应该以每小时至少5条记录结束,并且在15分钟之内它们之间的时间间隔。
当你的意思是,你需要5个记录每小时,你晚上11点12点和,或5分离(在有序阵列“指数”条款)值的时间差已是不到一个小时之间是什么意思? – Larme 2015-04-01 20:45:50
对于每个小时(晚上11点至12点),我至少需要5条记录,时间约15分钟。这样我可以说我有足够的数据来处理趋势变化。 – 2015-04-01 20:53:58