我正在寻找一种Python技术,以从熊猫数据框架中的平坦表格构建嵌套的JSON文件。例如怎么可能是大熊猫的数据帧表,例如:如何使用平面数据表构建嵌套记录的JSON文件?
teamname member firstname lastname orgname phone mobile
0 1 0 John Doe Anon 916-555-1234
1 1 1 Jane Doe Anon 916-555-4321 916-555-7890
2 2 0 Mickey Moose Moosers 916-555-0000 916-555-1111
3 2 1 Minny Moose Moosers 916-555-2222
采取并出口到一个JSON看起来像:通过创建类型的字典字典和倾倒
{
"teams": [
{
"teamname": "1",
"members": [
{
"firstname": "John",
"lastname": "Doe",
"orgname": "Anon",
"phone": "916-555-1234",
"mobile": "",
},
{
"firstname": "Jane",
"lastname": "Doe",
"orgname": "Anon",
"phone": "916-555-4321",
"mobile": "916-555-7890",
}
]
},
{
"teamname": "2",
"members": [
{
"firstname": "Mickey",
"lastname": "Moose",
"orgname": "Moosers",
"phone": "916-555-0000",
"mobile": "916-555-1111",
},
{
"firstname": "Minny",
"lastname": "Moose",
"orgname": "Moosers",
"phone": "916-555-2222",
"mobile": "",
}
]
}
]
}
我曾尝试这样做到JSON。这是我当前的代码:
data = pandas.read_excel(inputExcel, sheetname = 'SCAT Teams', encoding = 'utf8')
memberDictTuple = []
for index, row in data.iterrows():
dataRow = row
rowDict = dict(zip(columnList[2:], dataRow[2:]))
teamRowDict = {columnList[0]:int(dataRow[0])}
memberId = tuple(row[1:2])
memberId = memberId[0]
teamName = tuple(row[0:1])
teamName = teamName[0]
memberDict1 = {int(memberId):rowDict}
memberDict2 = {int(teamName):memberDict1}
memberDictTuple.append(memberDict2)
memberDictTuple = tuple(memberDictTuple)
formattedJson = json.dumps(memberDictTuple, indent = 4, sort_keys = True)
print formattedJson
这产生了以下输出。每个项目嵌套在“teamname”1或2下的正确级别,但如果记录具有相同的组名,则记录应嵌套在一起。我该如何解决这个问题,以便teamname 1和teamname 2每个嵌套2条记录?
[
{
"1": {
"0": {
"email": "[email protected]",
"firstname": "John",
"lastname": "Doe",
"mobile": "none",
"orgname": "Anon",
"phone": "916-555-1234"
}
}
},
{
"1": {
"1": {
"email": "[email protected]",
"firstname": "Jane",
"lastname": "Doe",
"mobile": "916-555-7890",
"orgname": "Anon",
"phone": "916-555-4321"
}
}
},
{
"2": {
"0": {
"email": "[email protected]",
"firstname": "Mickey",
"lastname": "Moose",
"mobile": "916-555-1111",
"orgname": "Moosers",
"phone": "916-555-0000"
}
}
},
{
"2": {
"1": {
"email": "[email protected]",
"firstname": "Minny",
"lastname": "Moose",
"mobile": "none",
"orgname": "Moosers",
"phone": "916-555-2222"
}
}
}
]
不幸的是,关于问题的高层次方法是好/正确/可能/等等的不幸的问题不在这里讨论。这就是说,我认为口述的方法*看起来很有希望。你应该使用你的其他问题来解决其余的细节问题,但记住要更新你收到的错误信息*以及你正在使用的代码,以便它们同步(否则你的问题是不可复制的) 。 –
我也试着调整这个答案:http://stackoverflow.com/questions/24374062/pandas-groupby-to-nested-json,但仍然没有骰子。 – spaine