将结构添加到列表并获取正确的输出

Question

我试图创建一个struct typedef movie_t并将其添加到列表中。它包含标题，导演，评分和制作年份。我的代码只是输出标题。我不明白为什么它不输出movie_t结构的所有成员？

例如，我已经定义：

movie_t *first_movie = {"The Outsiders","Francis Ford Coppola",'PG13',1983} 

但是当我运行我的程序只输出标题：

list[0] = The Outsiders 
list[1] = The Outsiders 
list[2] = The Outsiders 
list[3] = The Outsiders 
list[4] = The Outsiders 
list[5] = The Outsiders 
list[6] = The Outsiders 
list[7] = The Outsiders 
list[8] = The Outsiders 
list[9] = The Outsiders 

basiclist.h

#ifndef BASICLIST_H_ 
#define BASICLIST_H_ 

typedef struct node { 
    void * data;   /* pointer to data */ 
    struct node * next; /* pointer to next next node */ 
} node_t; 

int list_add(node_t ** list, void * data); 

#endif 

movie.h

#ifndef MOVIE_H 
#define MOVIE_H 
#define SIZE_LIMIT 25 
#define RATING_SIZE 5 

typedef enum {G, PG, PG13, R} rating_t; 

typedef struct { 
    char rating; 
    char title[SIZE_LIMIT]; 
    char director[SIZE_LIMIT]; 
    int year; 
}movie_t; 


void get_movie(movie_t * movie); 
void print_movie(const movie_t * movie); 

#endif /* MOVIE_H */ 

的main.c

#include "movie.h" 
#include <stdlib.h> 
#include <stdio.h> 
#include "basiclist.h" 

int list_add(node_t ** list, void * data) { 
    int ret = 0; 
    node_t * newnode = (node_t *) malloc(sizeof(node_t)); 
    if (newnode == NULL) { 
    ret = -1; 
    } 
    else { 
    newnode->data = data; 
    newnode->next = *list; 
    } 
    *list = newnode; 
    return ret; 
} 

int main (void) 
{ 
    int ii; 
    movie_t * new_movie; 
    movie_t *first_movie = {"The Outsiders","Francis Ford Coppola",'PG13',1983}; 
    node_t * list = NULL; 
    node_t * curr; 

    for(ii=0;ii<10;ii++) { 
    new_movie = (movie_t *) malloc(sizeof(int)); 
    *new_movie = *first_movie; 
    list_add(&list, new_movie); 
    } 

    ii = 0; 
    curr = list; 
    while (curr != NULL) { 
    printf("list[%d] = %s\n", ii, *((movie_t *) curr->data)); 
    ii++; 
    curr = curr->next; 
    } 
    printf("It worked!\n"); 
    return 0; 
} 

Answer 1

printf("list[%d] = %s\n", ii, *((movie_t *) curr->data));：movie_t和movie_t*不适合%s。您为move_t*制作自定义打印功能（print_movie）。

一些诸如

void print_movie(FILE* fp, const movie_t *m){ 
    static const char *raiting[] = { "G", "PG", "PG13", "R"}; 
    fprintf(fp, "%s\t%s\t%s\t%d\n", m->title, m->director, raiting[m->rating], m->year); 
} 

变化原型void print_movie(const movie_t * movie);到void print_movie(FILE* fp, const movie_t *m);
或更改名称，并从print_movie调用。

在主

变化printf("list[%d] = %s\n", ii, *((movie_t *) curr->data));
到print_movie(stdout, curr->data);

---

另外
变化movie_t *first_movie = {"The Outsiders","Francis Ford Coppola",'PG13',1983};
到movie_t first_movie = {"The Outsiders","Francis Ford Coppola", (char)PG13, 1983};

和

变化

typedef struct { 
    char rating; 
    char title[SIZE_LIMIT]; 
    char director[SIZE_LIMIT]; 
    int year; 
}movie_t; 

到

typedef struct { 
    char title[SIZE_LIMIT]; 
    char director[SIZE_LIMIT]; 
    char rating;//or rating_t rating; 
    int year; 
}movie_t; 

和

​​

到

for(ii=0;ii<10;ii++) { 
    new_movie = malloc(sizeof(*new_movie)); 
    *new_movie = first_movie; 
    list_add(&list, new_movie); 
}