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我想映射我的JSON到杰克逊的POJO类,但我收到空值。 如果我删除@JsonIgnoreProperties注解则抛出无法识别的属性Json字符串到Java对象映射失败与杰克逊
的JSON例外:
{
"TileLevel":[
],
"SystemLevel":[
{
"Title":"Test System Level Alert",
"Description":"<div class=\"ExternalClassA5AAC8F74C874A2D9DB8337EB6685B2A\"><p>Test System Level Alert<br></p><p>check the url http://www.google.com<br></p><p><span style=\"font-size:32px;\">formatting tested</span><br></p></div>",
"AnnouncementType":"System Level",
"ActiveF":null,
"TileName":null
}
],
"Announcements":[
{
"Title":"Test Announcement",
"Description":"<div class=\"ExternalClass16980D07D2FB4AB58A2E97C16B7626D3\"><p>Testing..... <img src=\"/sites/salesbk-CN/SiteCollectionImages/Salesbook%20Announcements/AllItems/00007-confiz-test-doc7.png\" alt=\"00007-confiz-test-doc7.png\" style=\"margin:5px;\" /><br></p></div>",
"AnnouncementType":"Announcement",
"ActiveF":null,
"TileName":null
}
]
}
我得到这个JSON作为字符串,然后尝试这个字符串到Java对象转换。
这里是我的POJO类:
public class SPOAnnouncement {
@JsonIgnoreProperties
private Map<String, List<List<SPOAnnouncements_Properties>>> TileLevel;
private Map<String, List<List<SPOAnnouncements_Properties>>> SystemLevel;
private Map<String, List<List<SPOAnnouncements_Properties>>> Announcements;
public Map<String, List<List<SPOAnnouncements_Properties>>> getTileLevel() {
return TileLevel;
}
public void setTileLevel(Map<String, List<List<SPOAnnouncements_Properties>>> tileLevel) {
TileLevel = tileLevel;
}
public Map<String, List<List<SPOAnnouncements_Properties>>> getSystemLevel() {
return SystemLevel;
}
public void setSystemLevel(Map<String, List<List<SPOAnnouncements_Properties>>> systemLevel) {
SystemLevel = systemLevel;
}
public Map<String, List<List<SPOAnnouncements_Properties>>> getAnnouncements() {
return Announcements;
}
public void setAnnouncements(Map<String, List<List<SPOAnnouncements_Properties>>> announcements) {
Announcements = announcements;
}
}
public class SPOAnnouncements_Properties {
private String Title;
private String Description;
private String AnnouncementType;
private String ActiveF;
private String TileName;
public String getTitle() {
return Title;
}
public void setTitle(String title) {
Title = title;
}
public String getDescription() {
return Description;
}
public void setDescription(String description) {
Description = description;
}
public String getAnnouncementType() {
return AnnouncementType;
}
public void setAnnouncementType(String announcementType) {
AnnouncementType = announcementType;
}
public String getActiveF() {
return ActiveF;
}
public void setActiveF(String activeF) {
ActiveF = activeF;
}
public String getTileName() {
return TileName;
}
public void setTileName(String tileName) {
TileName = tileName;
}
}
我的测试方法来验证,如果结果已被映射到JSON对象:
@Test
public void convertJsonToObject() throws IOException {
ObjectMapper mapper = new ObjectMapper();
mapper.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);
SPOAnnouncement spoAnnouncement = mapper.readValue(response, SPOAnnouncement.class);
System.out.print(spoAnnouncement);
}
无关:请阅读有关Java命名约定。字段名称也是camelCase。你去UpperCase的习惯会让其他人感到困惑。 – GhostCat
然后:阅读[mcve]。显示**最小**示例。为什么要建立一个3层嵌套的例子,当可能更简单的事情会做? – GhostCat
神圣的guacomoley。请编辑你的问题,并使所有类字段camelCase。现在很难看到什么是类和什么是一个领域。 – Tschallacka