SQL服务器 - 查询帮助

MEDIA

MediaID  MediaTypeID Title 
--------------------------------------------- 
100   25   Photo of Anton Oliver 
200   25   Photo of Hika Eliot

CAMPAIGNS（活动使用媒体和属于池）

CampaignID MediaID PoolID 
---------------------------- 
1   100  1 
2   100  2 
3   200  1

CAMPAIGN藏

PoolID  PoolName 
-------------------- 
1   Pool1 
2   Pool2 
3   Pool3

给出了具体的campaignID和poolID传递给查询，我想下面的选择查询，以确定媒体是否属于通过运动和/或池

SELECT m.* 
FROM media m 
<!--- whatever required joins --->

所以，结果记录会看是这样的：

MediaData

MediaID MediaTypeID Title BelongsToCampaign BelongsToPool 
---------------------------------------------------------------- 
1   25    xyz  0     1

我希望这是有道理的。

来源

2011-09-05 user460114

你可以做这样的事情：

Select MediaID,MediaTypeID,Title,ISNULL(c.CampaignID,0) as BelongsToCampaign,ISNULL(p.PoolID,0) as BelongsToPool 
From Media m 
LEFT OUTER JOIN Campaign c on m.MediaID=c.MediaID 
LEFT OUTER JOIN Pools p on p.PoolID=c.PoolID 
where [email protected] OR [email protected]

问候

来源

2011-09-05 23:39:32 BizApps

+1 yep。这应该很好。 – deutschZuid

select m.MediaID, m.MediaTypeID, m.mediaTitle as Title, c.CampaignID as BelongsToCampaign,  cp.PoolID as belongsToPool 
from campaings c, media m, campaign_pools cp 
where (m.mediaid = c.mediaid) and (c.poolId = cp.poolId) and 
(c.campaignID = [your variable] or cp.PoolId = [your other variable])

来源

2011-09-05 23:37:46 user710502

这不是标准的tsql语法。我认为没有指定连接的类型，逗号默认为内部连接，这不符合他的要求。除此之外，我认为他希望0为null值，所以在select部分中需要一个isnull语句。 – deutschZuid

不要使用来自广告系列c，媒体m，...的旧式''JOIN语法 - 它是遗留的，如果您碰巧忘记了JOIN条件会很危险，因为您最终拥有JOIN条件和实际的WHERE在WHERE子句中将所有混合在一起的条件 - 使用** ANSI JOIN **语法（'INNER JOIN'，'LEFT OUTER JOIN'）来代替！ –

我不知道从你的天赋，你想要的结果集返回所有媒体或只有特定的子集（按@ BizApps的答案） - 发布两行以上的示例数据可能对此有所帮助;）

以下联合使用四种可能的子集：删除或注释掉不需要的子集。我相信你可以看到CTE可以用来减少代码中的重复：

SELECT m.*, t.BelongsToCampaign, t.BelongsToPool 
    FROM (
     -- Campaign INTERSECT Pool 
     SELECT c.MediaID, 1 AS BelongsToCampaign, 1 AS BelongsToPool 
      FROM CAMPAIGNS AS c 
     WHERE c.CampaignID = @CampaignID 
     INTERSECT 
     SELECT MediaID, 1, 1 
      FROM CAMPAIGN_POOLS AS p JOIN CAMPAIGNS AS c ON p.PoolID = c.PoolID 
     WHERE p.PoolID = @PoolID 

     -- Campaign EXCEPT Pool 
     UNION 
     SELECT c.MediaID, 1, 0 
      FROM CAMPAIGNS AS c 
     WHERE c.CampaignID = @CampaignID 
     EXCEPT 
     SELECT MediaID, 1, 0 
      FROM CAMPAIGN_POOLS AS p JOIN CAMPAIGNS AS c ON p.PoolID = c.PoolID 
     WHERE p.PoolID = @PoolID 

     -- Pool EXCEPT Campaign 
     UNION 
     SELECT MediaID, 0, 1 
      FROM CAMPAIGN_POOLS AS p JOIN CAMPAIGNS AS c ON p.PoolID = c.PoolID 
     WHERE p.PoolID = @PoolID 
     EXCEPT 
     SELECT c.MediaID, 0, 1 
      FROM CAMPAIGNS AS c 
     WHERE c.CampaignID = @CampaignID 

     -- Media in neither Pool nor Campaign 
     UNION 
     SELECT m.MediaID, 0, 0 
      FROM MEDIA AS m 
     EXCEPT 
     SELECT c.MediaID, 0, 1 
      FROM CAMPAIGNS AS c 
     WHERE c.CampaignID = @CampaignID 
     EXCEPT 
     SELECT MediaID, 1, 0 
      FROM CAMPAIGN_POOLS AS p JOIN CAMPAIGNS AS c ON p.PoolID = c.PoolID    
     WHERE p.PoolID = @PoolID 
     ) AS t 
     JOIN MEDIA AS m ON m.MediaID = t.MediaID;

来源

2011-09-06 14:46:13 onedaywhen

SQL服务器 - 查询帮助

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