从Table1中获取表中缺少table2 oracle的行吗？

Question

我有两个表如下。我正在使用Oracle 10g

TableA 
--------- 
id Name 
--- ---- 
1 abc 
2 def 
3 xxx 
4 yyy 

TableB 
--------- 
id Name 
--- ---- 
1 abc 
2 def 

TableC 
--------- 
id Name 
--- ---- 
1 abc 
2 def 

现在我需要获得ids from TableA which are not there in TableB and TableC。我怎样才能做到这一点，而不使用NOT IN子句？

请帮帮我！

谢谢！

Answer 1

请尝试：

SELECT 
    a.ID, 
    a.NAME 
FROM 
    TABLEA a LEFT JOIN TABLEB b ON a.ID=b.ID 
    LEFT JOIN TABLEC c ON a.ID=c.ID 
WHERE 
    b.ID IS NULL AND 
    c.ID IS NULL; 

Answer 2

select * from TableA 
minus 
select * from TableB 

---

编辑：

不在B和C同时：

select * from TableA 
minus (
    select * from TableB 
    intersect 
    select * from TableC 
) 

不在B或在C：

select * from TableA 
minus 
select * from TableB 
minus 
select * from TableC 

Answer 3

select a.id 
from tableA a,tableB b,tableC c 
where a.id != b.id and a.id!=c.id 

这是罚款？

Answer 4

select * from TableA 
minus 
(select * from TableB 
union 
select * from TableC)