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**以下是老师和登录学生的两种模式,一位老师可以教多个部分,多个学生可以在同一部分。因此部分字段不能是外键。如果我想查明所有的课程都是由某个学生完成的,我该怎么做?是否有任何简单的django查询就像sql一样?怎么办? **简单的django加入无外键查询

class Teacher(models.Model): 
    username=models.CharField(max_length=50) 
    password=models.CharField(max_length=89) 
    course=models.CharField(max_length=30) 
    section=models.CharField(max_length=30) 

class LoginStudent(models.Model): 
    username=models.CharField(max_length=50) 
    password=models.CharField(max_length=89) 
    section=models.CharField(max_length=30) 
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你有没有试过做这件事。 – CurseStacker

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你应该检查https://docs.djangoproject.com/en/1.8/topics/auth/customizing/#extending-the-existing-user-model – cdvv7788

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@CurseStacker newobj = teacher.objects.raw('select * from app_teacher t,app_loginstudent l其中l.section = t.section和l.username =%s',[name])..name是学生姓名,我想列出其姓名 –

回答

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OK,我会建议坚持从Django的默认的用户系统,并建立了特定类型的一到一个配置文件需要的地方。后者上,你可以根据外键的值的用户之间进行区分,或者你可以实现其绑定到用户类型

from django.db.models.query_utils import Q 


# for example, this could be a way to extend users to hold teachers and students 
class TeacherProfile(models.Model): 
    user = models.OneToOneField(User, related_name='teacher_profile') 
    # other relevant teacher profile items 
ONLY_TEACHERS_FILTER = Q(teacher_profile__isnull=False) & Q(student_profile__isnull=True) 


class StudentProfile(models.Model): 
    user = models.OneToOneField(User, related_name='student_profile') 
    # other relevant student profile items 
    sections = models.ManyToManyField('Section', related_name='students') # mind the quotes to Section name 


class Section(models.Model) 
    name = models.CharField(max_length=50) 
    # other section fields goes here... 


class Course(models.Model): 
    name = models.CharField(max_length=50) 
    teacher = models.ForeingKey(User, related_name='courses', limit_choices_to=ONLY_TEACHERS_FILTER) 
    sections = models.ManyToManyField(Section, related_name='courses') 

我们问题的答案是什么,其学生参加课程的权限到:

queryset = Course.objects.filter(section__students__in=[user]) 

希望它有帮助!