1
我只是一个初学者,试图按照教程。我确实搜索了最接近的问题,尝试了其中的几个。他们都不适合我。我只需要一些可能出错的线索。谢谢。C#web表单提交的数据无法插入sql数据库
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.Data.SqlClient;
namespace Company
{
public partial class ContactUs : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
}
public void update(string FirstName, string LastName, string EmailAddress, string MobileNumber, string category, string message)
{
SqlConnection conn = new SqlConnection(GetConnectionString());
string sql = "INSERT INTO ContactInformation (GUID,FirstName, LastName, EmailAddress, Number, Category, Message) VALUES "
+ " (@GUID,@FirstName,@LastName,@EmailAddress,@Number,@category,@message)";
Guid guid = Guid.NewGuid();
string guidString = guid.ToString();
try
{
conn.Open();
SqlCommand cmd = new SqlCommand(sql, conn);
SqlParameter[] p = new SqlParameter[7];
p[0] = new SqlParameter("@GUID", SqlDbType.UniqueIdentifier,50);
p[1] = new SqlParameter("@FirstName", SqlDbType.VarChar,50);
p[2] = new SqlParameter("@LastName", SqlDbType.VarChar,50);
p[3] = new SqlParameter("@EmailAddress", SqlDbType.VarChar,50);
p[4] = new SqlParameter("@Number", SqlDbType.VarChar,50);
p[5] = new SqlParameter("@Category", SqlDbType.VarChar,50);
p[6] = new SqlParameter("@Message", SqlDbType.VarChar,50);
p[0].Value = guid;
p[1].Value = FirstName;
p[2].Value = LastName;
p[3].Value = EmailAddress;
p[4].Value = MobileNumber;
p[5].Value = category;
p[6].Value = message;
for (int i = 0; i < p.Length; i++)
{
cmd.Parameters.Add(p[i]);
}
cmd.CommandType = CommandType.Text;
cmd.ExecuteNonQuery();
}
catch (System.Data.SqlClient.SqlException ex)
{
string msg = "Insert Error:";
msg += ex.Message;
throw new Exception(msg);
}
finally
{
conn.Close();
}
}
public string GetConnectionString()
{
return System.Configuration.ConfigurationManager.ConnectionStrings["ContactInformation"].ConnectionString;
}
protected void btnSubmit_Click(object sender, EventArgs e)
{
if (!IsPostBack)
{
Validate();
update(txtFirstName.Text,
txtLastName.Text,
txtEmail.Text,
txtNumber.Text,
DropDownList1.SelectedItem.Text,
txtMessage.Text);
Response.Write("Record was successfully added!");
//ClearForm(Page);
}
}
public static void ClearForm(Control Parent)
{
if (Parent is TextBox)
{ (Parent as TextBox).Text = string.Empty; }
else
{
foreach (Control c in Parent.Controls)
ClearForm(c);
}
}
}
}
连接字符串位于web.config文件中。
<connectionStrings>
<add name="ContactInformation" connectionString="datasource=database;initial catalog=ContactInformation;Integrated Security=SSPI;userid=xxx;password=xxx;"/>
</connectionStrings>
我部署了我的本地计算机上的网站,并尝试测试它在互联网上Explorer.And在另一边,我打开数据库管理工具,该表仍是空的。
嗨@MethodMan对不起,我不熟悉张贴。我刚编辑我的代码。我没有收到代码错误。我只是无法将任何数据插入数据库。 – GoResistanceLi
您是否尝试过使用调试器逐行调试代码行?它是否遵循了您期望的代码路径? – mason
我认为你应该看看如何正确创建参数,当你逐步完成应该能够评估的代码和所有参数值时。也在这一行上放置一个断点,看看它是否到达这一行'string msg =“Insert Error:”; 1'你还应该将你的Sql对象包装在一个'using(){}'的周围,而不是处理所有的创建对象 – MethodMan