用户身份验证试图字符串转换为整数

Question

Possible Duplicate:
Can't convert String into integer in ruby/ruby-on-rails

我正在通过教程林达学习轨和我遇到的一个问题。我已经构建了一个AccessController以与我拥有的AdminUser模型一起工作。我正在使用字符串/时间盐组合并将其保存到Db，然后尝试使用登录表单进行身份验证。下面是AccessController的

一些代码

def attempt_login 
authorized_user = AdminUser.authenticate(params[:username], params[:password]) 
#authorized_user = nil 

if authorized_user 
    flash[:notice] = "You are logged in now" 
    redirect_to(:action => 'menu') 
else 
    flash[:notice] = "invalid username/password combo" 
    redirect_to(:action => 'login') 
end 

末

然后一些从我的模型，我定义的身份验证方法：

def self.authenticate(username="", password="") 

    user = AdminUser.find_by_username(username) 
    if user && user.password_match?(password) 
     return user 
    else 
     return false 
    end 
end 

    def password_match?(password="") 
    hashed_password == AdminUser.hash_with_salt(password, salt) 
end 

所有hash_with_salt方法确实是以盐从数据库中进行该用户并确保输入的密码被盐分加密/加密。这里是我不断得到的错误：

TypeError in AccessController#attempt_login 

can't convert String into Integer 

Rails.root: /Users/UNAME/Sites/simple_cms 
Application Trace | Framework Trace | Full Trace 

activesupport (3.1.3) lib/active_support/descendants_tracker.rb:22:in `delete' 
activesupport (3.1.3) lib/active_support/descendants_tracker.rb:22:in `block in clear' 
activesupport (3.1.3) lib/active_support/descendants_tracker.rb:20:in `each' 
activesupport (3.1.3) lib/active_support/descendants_tracker.rb:20:in `clear' 
railties (3.1.3) lib/rails/application/bootstrap.rb:56:in `block (2 levels) in <module:Bootstrap>' 
activesupport (3.1.3) lib/active_support/callbacks.rb:395:in `_run_cleanup_callbacks' 
activesupport (3.1.3) lib/active_support/callbacks.rb:81:in `run_callbacks' 
actionpack (3.1.3) lib/action_dispatch/middleware/reloader.rb:72:in `rescue in call' 
actionpack (3.1.3) lib/action_dispatch/middleware/reloader.rb:67:in `call' 
rack (1.3.6) lib/rack/sendfile.rb:101:in `call' 
actionpack (3.1.3) lib/action_dispatch/middleware/remote_ip.rb:48:in `call' 
actionpack (3.1.3) lib/action_dispatch/middleware/show_exceptions.rb:47:in `call' 
railties (3.1.3) lib/rails/rack/logger.rb:13:in `call' 
rack (1.3.6) lib/rack/methodoverride.rb:24:in `call' 
rack (1.3.6) lib/rack/runtime.rb:17:in `call' 
activesupport (3.1.3) lib/active_support/cache/strategy/local_cache.rb:72:in `call' 
rack (1.3.6) lib/rack/lock.rb:15:in `call' 
actionpack (3.1.3) lib/action_dispatch/middleware/static.rb:53:in `call' 
railties (3.1.3) lib/rails/engine.rb:456:in `call' 
rack (1.3.6) lib/rack/content_length.rb:14:in `call' 
railties (3.1.3) lib/rails/rack/log_tailer.rb:14:in `call' 
rack (1.3.6) lib/rack/handler/webrick.rb:59:in `service' 
/Users/UNAME/.rvm/rubies/ruby-1.9.3-p0/lib/ruby/1.9.1/webrick/httpserver.rb:138:in `service' 
/Users/UNAME/.rvm/rubies/ruby-1.9.3-p0/lib/ruby/1.9.1/webrick/httpserver.rb:94:in `run' 
/Users/UNAME/.rvm/rubies/ruby-1.9.3-p0/lib/ruby/1.9.1/webrick/server.rb:191:in `block in start_thread' 

任何帮助将不胜感激。我确定我正在做与教程完全一样的东西，但是由于Ruby/Rails版本的不同，可能会有错误？在这方面搜索了几个小时，其中大部分讨论inject（）方法的结果都没有帮助。再次感谢！

Answer 1

我有这个相同的问题，并花了数小时试图解决它。原来，我的方法已经离开的教程，叫我删除了一些视频事先：

def self.hash(password="") 
    Digest::SHA1.hexdigest(password) 
end 

在本教程中，这已经改为方法

def self.make_salt(username="") 
    Digest::SHA1.hexdigest("Use #{username} with #{Time.now} to make salt") 
end 

def self.hash_with_salt(password="", salt="") 
    Digest::SHA1.hexdigest("Put #{salt} on the #{password}") 
end 

一旦我评论这种方法，错误消失了。我仍然不明白为什么这个错误首先出现。我添加了一个问题和更多详细信息here。

Answer 2

下面是一些常见的方式将造成错误：

my_method :name => "dan", :age => 23 

def my_method(*args) 
    puts args[:name] # ERROR. thinks that args looks like {:name => "dan3, :age => 23} 
    puts args[0][:name] # SUCCESS. args is actually an array because of the *splat: 
         # args = [{:name => "dan", :age => 23}] 
end 

或者

params = {} 
params[:greeting] = "howdy" 
params[:greeting][:bye] # ERROR. You're basically calling "howdy"[:bye]. 
         # Note that "howdy"[0] returns "h". 

这不是一个答案，但它会是难读注释。也许它可以帮助你看到寻找什么。

例如，您传递字符串的某些代码可能会期望散列。