Python将字符串转换为整数？

Question

比方说，我有一个Python字符串是这样的：

Some first text: 2342 
Another line here: 284 
Maybe third line: 458 
And forth line: 199 

，我想从这个字符串创建4个整数变量，使得VAR =（无论在线路1号）。和var2 =（第2行中的任何数字）..等等。

这怎么可能？

Answer 1

您可以将所有编号的数组：

s = '''\ 
Some first text: 2342 
Another line here: 284 
Maybe third line: 458 
And forth line: 199''' 

print [int(l.split(':')[1]) for l in s.split('\n')] 

输出：

[2342, 284, 458, 199] 

然后数组的第一个元素将对应于第一线等

Answer 2

试试这个：

words = somestring.split() 
    for i in range(len(words)): 
     try: 
      locals()['int_%s'%(i)] = int(words[i]) 
     exept: 
      pass 

Answer 3

您可以使用for循环和is_digit方法。

这样的：

# let's guess input text is called TEXT. 
TEXT = '''\ 
Some first text: 2342 
Another line here: 284 
Maybe third line: 458 
And forth line: 199''' 

# we can make like this: 
splited_TEXT = TEXT.split('\n') 
# make new(wanted) dictionary 
new_dict = {} 

# then use for loop: 
for num, sentence in enumerate(splited_TEXT): 
    for word in sentence.split(' '): # split by space 
     if word.is_digit: # check if word is digit 
      new_dict[num] = word 
      continue 
print(new_dict) 

然后你就可以检查{0：2342 1：284 ...}

Answer 4

我发现，这个简单的线路工程：

[int(s) for s in TEXT.split() if s.isdigit()] 

为如上所述的TEXT。