在水果项的数组创建所选项目的数组

Question

我有一个元素的数组与索引数组从第一阵列删除：

如果

var array = ["a", "b", "c", "d", "e", "f", "g", "h", "i"]  
let indicesToDelete = [4, 8] 

let reducedArray = indicesToDelete.reverse().map { array.removeAtIndex($0) } 
reducedArray // prints ["i","e"] 

我的数组是这样的：

class Fruit{ 
let colour: String 
let type: String 
init(colour:String, type: String){ 
    self.colour = colour 
    self.type = type 
    } 
} 

var arrayFruit = [Fruit(colour: "red", type: "Apple"),Fruit(colour: "green", type: "Pear"), Fruit(colour: "yellow", type: "Banana"),Fruit(colour: "orange", type: "Orange")] 
let indicesToDelete = [2,3] 

如果我只是使用上面的代码，我得到一个错误。

let reducedArray = indicesToDelete.reverse().map { arrayFruit.removeAtIndex($0) }////// error here 

我的问题是fruitArray是由对象组成的，我不知道如何调整上面的代码。

Answer 1

减小的数组不是map的结果，而是原始数组，即arrayFruit。我建议不使用map但forEach，并把它写这样的：

class Fruit{ 
    let colour: String 
    let type: String 
    init(colour:String, type: String){ 
     self.colour = colour 
     self.type = type 
    } 
} 

var arrayFruit = [Fruit(colour: "red", type: "Apple"),Fruit(colour: "green", type: "Pear"), Fruit(colour: "yellow", type: "Banana"),Fruit(colour: "orange", type: "Orange")] 
let indicesToDelete = [2,3] 

indicesToDelete.sort(>).forEach { arrayFruit.removeAtIndex($0) } 
arrayFruit // [{colour "red", type "Apple"}, {colour "green", type "Pear"}]