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我有下面的代码。它试图基本处理从jsf表单提交的数据,然后将数据插入到数据库中的表中。现在我们安装的数据库已经很老了......它是sql server 2000,所以我用jtds作为驱动程序。的代码:Java PreparedStatement错误
public void dbConnect(String db_connect_string,
String db_userid,
String db_password)
{
try {
Class.forName("net.sourceforge.jtds.jdbc.Driver");
Connection conn = DriverManager.getConnection(db_connect_string,
db_userid, db_password);
System.out.println("connected");
dateSubmitted = "dasdasd";
/*HERE THE STATEMENTS TO INSERT*/
java.sql.PreparedStatement insertData = null;
String insertStatement = "INSERT INTO SLMDATA VALUES(?,?,?,?,?,?,?,?,?,?,"
+ "?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)";
insertData = conn.prepareStatement(insertStatement);
insertData.setString(1, serviceLogger);
insertData.setString(2, dateSubmitted);
insertData.setString(3, serviceName);
insertData.setString(4, department);
insertData.setString(5, division);
insertData.setString(6, businessServiceDescription);
insertData.setString(7, technicalServiceDescription);
insertData.setString(8, serviceCustomer);
insertData.setString(9, serviceCriticality);
insertData.setString(10, serviceRequestSystem);
insertData.setString(11, serviceCategory);
insertData.setString(12, serviceHours);
insertData.setString(13, availabilityTarget);
insertData.setString(14, lowIncidentResponseScale);
insertData.setString(15, lowIncidentResponseHrsType);
insertData.setString(16, lowResponseTimeText);
insertData.setString(17, mediumIncidentResponseScale);
insertData.setString(18, mediumIncidentResponseHrsType);
insertData.setString(19, mediumResponseTimeText);
insertData.setString(20, highIncidentResponseScale);
insertData.setString(21, highIncidentResponseHrsType);
insertData.setString(22, highResponseTimeText);
insertData.setString(23, lowIncidentResolutionScale);
insertData.setString(24, lowIncidentResolutionHrsType);
insertData.setString(25, lowResolutionTimeText);
insertData.setString(26, mediumIncidentResolutionScale);
insertData.setString(27, mediumIncidentResolutionHrsType);
insertData.setString(28, mediumResolutionTimeText);
insertData.setString(29, highIncidentResolutionScale);
insertData.setString(30, highIncidentResolutionHrsType);
insertData.setString(31, highResolutionTimeText);
insertData.setString(32, blockTime);
insertData.setString(33, impactedServices);
insertData.setString(34, operationalDependencies);
insertData.setString(35, disasterAvailable);
insertData.setString(36, configurationItems);
insertData.executeUpdate();
conn.close();
FacesContext.getCurrentInstance().getExternalContext().dispatch("thankyou.xhtml");
} catch (Exception e) {
e.printStackTrace();
}
}
public void callConnection(){
dbConnect("jdbc:jtds:sqlserver://host;", "username",
"password");
}
和GlassFish服务器控制台输出显示:
java.sql.SQLException中:无效的对象名称SLMDATA'。
SLMDATA是表的名称,并且确定它是正确的。当我通过断点功能遍历代码时,我会到达executeQuery,然后事情就会失去控制。我研究了所有变量的内容,并且都是有效的。任何想法是怎么回事?一直卡在这一段时间
可能的重复项:[here](http://stackoverflow.com/questions/909599/java-mssql-java-sql-sqlexception-invalid-object-name-tablename)和[there](http:// stackoverflow .com/questions/6647846/invalid-object-name) - 你可以尝试一个简单的'SELECT * FROM SLMDATA'来查看你是否得到相同的错误。 – assylias 2012-03-26 09:48:51
谢谢你做了@assylias:D真的很感激它,很抱歉忽略那个:) – 2012-03-26 09:53:13