自定义Feed只显示关注用户的文章

Question

我一直在参考this rails教程，试图创建一个只有属于已接受我的好友请求的用户的文章出现在我的提要中的Feed。然而，我有一个不同的模式和用户模型从教程（我有一个额外的步骤，朋友请求正在等待接受）。在我的用户模型中的下面的方法不会过滤掉没有被接受的友谊，因此未经证实的朋友的文章正在出现我的馈送，这不是我想要的。

user.rb

has_many :friendships 
    has_many :received_friendships, class_name: "Friendship", foreign_key: "friend_id" 
    has_many :active_friends, -> { where(friendships: { accepted: true}) }, through: :friendships, source: :friend 
    has_many :received_friends, -> { where(friendships: { accepted: true}) }, through: :received_friendships, source: :user 
    has_many :pending_friends, -> { where(friendships: { accepted: false}) }, through: :friendships, source: :friend 
    has_many :requested_friendships, -> { where(friendships: { accepted: false}) }, through: :received_friendships, source: :user 

    def feed 
    friend_ids = "SELECT friend_id FROM friendships 
        WHERE user_id = :user_id" 
    Article.where("user_id IN (#{friend_ids}) 
        OR user_id = :user_id", user_id: id) 
    end 

schema.rb

create_table "friendships", force: :cascade do |t| 
    t.integer "user_id" 
    t.integer "friend_id" 
    t.boolean "accepted", default: false 
    t.datetime "created_at", null: false 
    t.datetime "updated_at", null: false 
    end 

页控制器

def home 
    @feed = current_user.feed.all 
end 

home.html.erb

<%= render @feed %> 

Answer 1

对于你的情况，我认为关键是这里WHERE（USER_ID =：USER_ID并接受= TRUE），我得到接受了友谊架构字段。

def feed 
    friend_ids = "SELECT friend_id FROM friendships 
        WHERE (user_id = :user_id AND accepted = 't')" 
    Article.where("user_id IN (#{friend_ids}) 
        OR user_id = :user_id", user_id: id) 
    end