做分组和总和SQL

我想总结一列，而分组另一列。 SQL一致
给我两个单独的行。做分组和总和SQL

以下是我的剧本，我的结果：

Select A.client, A.store, A.Type as 'Ticket Type', A.[bizdate] as 'DATE',  
sum(cast(round(c.[Amount2],2) as decimal (20,0))) 'QTY', c.SKU, c.[DESC], 
sum(cast(round(c.[Amount1],2)as decimal(20,2))) as 'Total' 


From Mydatabase A inner join mydatabase.dbo.TicketHeader B on A.  
[ticket] = b.[ticket] and a.[yyyymmdd] = b.[yyyymmdd] 
inner join mydatabase.dbo.ticketdetail C on C.[ticketheaderid] = 
b.[id] and c.[class] = a.[class] 

where 
A.Store = @store 
and a.yyyymmdd = @yyyymmdd 
and c.class <> 'balance' 
and c.Subtype <> 'cancelled' 
and a.type NOT IN  
('SKU','Total','CASH','CHANGE','NA','TAX1','TAX2','TAX3','TAX4','CHARGE',  
'Delivery Service', 'Tip') 
and c.[DESC] <> 'NA' 
and c.sku = '300129' 

group by c.sku, c.[DESC],a.store, a.type, a.bizdate, a.client, c.[Amount2],  
c.[Amount1] 
order by [ticket type] 

client, Store TicketType   date  qty SKU Description Amount 
1  2404 CURBSIDE/TO GO 20170214 1 300129 Beef TACO 2.00 
1  2404 DINE IN   20170214 1 300129 Beef TACO 2.00 
1  2404 DINE IN   20170214 2 300129 Beef TACO 4.00 
1  2404 FOODSBY   20170214 2 300129 Beef TACO 4.00

我想组餐费牛肉TACO一个线，而求和
量。

来源

2017-02-15 Brad Jarrett

从您的群组中取出金额1和金额2。你使用这些作为你的总量，把它们放在组中是起反作用的。 –

为什么哦为什么你将日期存储为整数或varchar？ –

当我把它们拉出来时，它表示它需要在组中。将日期存储为varchar ...这可能是我的问题不是吗？ –

这里有几个设计和代码问题。诸如“金额1”和“金额2”之类的信息可能表示可能的差异正常化。并且别名A，B，C是一个坏习惯，因为它使维护方式比应该更加困难。 http://sqlblog.com/blogs/aaron_bertrand/archive/2009/10/08/bad-habits-to-kick-using-table-aliases-like-a-b-c-or-t1-t2-t3.aspx

除了从格式化的角度来看，你的代码是一团糟，这是很痛苦的工作。添加一些空白区域，让你的分组位于，这应该很好。

Select A.client 
    , A.store 
    , A.Type as 'Ticket Type' 
    , A.[bizdate] as 'DATE' 
    , sum(cast(round(c.[Amount2],2) as decimal (20,0))) 'QTY' 
    , c.SKU 
    , c.[DESC] 
    , sum(cast(round(c.[Amount1],2)as decimal(20,2))) as 'Total' 
From Mydatabase A 
inner join mydatabase.dbo.TicketHeader B on A.[ticket] = b.[ticket] 
             and a.[yyyymmdd] = b.[yyyymmdd] 
inner join mydatabase.dbo.ticketdetail C on C.[ticketheaderid] = b.[id] and c.[class] = a.[class] 
where 
    A.Store = @store 
    and a.yyyymmdd = @yyyymmdd 
    and c.class <> 'balance' 
    and c.Subtype <> 'cancelled' 
    and a.type NOT IN  
    (
     'SKU','Total','CASH','CHANGE','NA','TAX1','TAX2','TAX3','TAX4','CHARGE','Delivery Service', 'Tip' 
    ) 
    and c.[DESC] <> 'NA' 
    and c.sku = '300129' 
group by A.client 
    , A.store 
    , A.Type 
    , A.[bizdate] 
    , c.SKU 
    , c.[DESC] 
order by [ticket type]

来源

2017-02-15 17:57:53

做分组和总和SQL

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