php mysql querys在Xampp中工作，但不是我在AWS云中的LAMP栈

Question

这只是我写的一个测试用例，但我的主要问题是我的整个 应用程序工作本地连接到MySQL并返回几千个 记录我打开错误报告在EALL forthe页面上，我没有得到任何错误，我实际得到的这个测试用例的输出是数字号码数字数字五次，这没有任何意义，因为我在这个例子中通过主键抓取一行 。任何方式我是新的PHP所以任何参考 从xammp到灯将不胜感激。 url是http://prestigeworldwide.me/game/谢谢你提前

<?php 
$servername = "localhost"; 
$username = "root"; 
$password = "Mypass"; 
$dbname = "test"; 
$conn = mysqli_connect($servername, $username, $password, $dbname); 
$sqltest = sprintf("SELECT num, num2 FROM mytest WHERE num = 2"); 

if (!$conn) { 
    die("Connection failed: " . mysqli_connect_error()); 
} 

$resulttest = mysqli_query($conn, $sqltest); 

foreach($resulttest as $row){ 
    echo("Number".$row['num'].$row['num2']); 
} 

mysqli_close($conn);; 
?> 

Answer 1

我建议你使用pdo。 Take a look here.

$dbtype  = "mysql"; 
    $dbhost  = "localhost"; 
    $dbname  = "*****"; 
    $dbuser  = "*****"; 
    $dbpass  = "*****"; 

    try{ 
    $conn = new PDO("mysql:host=$dbhost;dbname=$dbname; charset=utf8", $dbuser,$dbpass); 
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
} catch (PDOException $e){ 
    echo $e->getMessage(); 
} 
$sql = "SELECT num, num2 FROM mytest WHERE num = '2'"; 
$q = $conn->query($sql); 

while ($r = $q -> fetch()): 
    echo "Number" . $r['num'] . $r['num2']); 
endwhile;