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我有两个字符数组,我想做一个2维数组。 但字符值似乎造成了一个问题,就像我试图在2D数组中初始化它们一样。如何在C中初始化这个二维数组?
什么是初始化这种类型的数组的正确方法? 函数“trumplar()”可以正常工作,也可以像我期望的那样工作。
2D字符数组x [22] [22]函数“trumpsterFire()”无法正确初始化。
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
void trumplar(){
int len = 22;
char a[25]={0x3f,0x6,0x5b,0x4f,0x66,0x6d,0x7d,0x7,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0x3d,0x76,0x1e,0x38,0x38,0x6d,0x00};
char L[25]="abcdefghjlpsS";
int i;
for (i = 0; i <=len; i++){
char hit=L[i];
char urd=a[i];
printf("The %d, Value of a is:%c\t Hex val: %c\n",i,hit,urd);
}
}
void trumptsterFire(){
//int xlen = 22;
char x[22][22]={
{0x3f,0},{0x6,1},{0x5b,2},
{0x4f,3},{0x66,4},{0x6d,5},
{0x7d,6},{0x7,7},{0x7f,8},
{0x6f,9},{0x77,a},{0x7c,b},
{0x39,c},{0x5e,d},{0x79,e},
{0x71,f},{0x3d,g},{0x76,h}
,{0x1e,j},{0x38,l},{0x38,p},
{0x6d,s},{0x00,S}
};
}
int main(){
trumplar();
trumptsterFire();
return 0;
}
您是否将最后一个'\ 0'元素添加到数组? –
您的阵列尺寸没有多大意义。你已经有了'char x [22] [22]'(由22个字符组成的22个数组的数组),然后是一个匹配char x [23] [2]的初始化列表(2个字符的23个数组) ...(忽略缺失的单引号) – Dmitri