2012-06-28 68 views
0

我有这个java代码:多个SQL查询单查询加盟

ArrayList<MessageMap> ids = getNewMail(UserID, type, maxIdMessage); 
Message[] message = new Message[ids.size()]; 
if(ids.size()>0){ 
    ResultSet rs; 
    int j =0; 
    for(MappaMessaggi i : ids){ 
     pstmt = conn.prepareStatement("SELECT * FROM Messaggi WHERE MessageID = ?"); 
     pstmt.setInt(1, i.getMessageID()); 
     rs = pstmt.executeQuery(); 
     rs.next(); 
     . 
     . 
     . 
    } 

其中getNewMail是:

public synchronized ArrayList<MessageMap> getNewMail(int UserID,int type,int max){ 
    ArrayList<MessageMap> map = new ArrayList<MessageMap>(); 
    try { 
     pstmt = conn.prepareStatement("SELECT * FROM MessageMap WHERE UserID = ? AND TipoID = ? AND MessageID > ?"); 
     . 
     .//fill arraylist with resultSet 
     . 
} 

我知道这是有可能做同样的只有一个查询,但我不知道如何......有人能睁开我的眼睛吗? :) 谢谢!!!

编辑:我尝试:

SELECT i.* 
FROM Messaggi AS i 
INNER JOIN MessageMap AS p i.MessageID = p.MessageID 
WHERE p.MessageID = 1 AND p.UserID = 1 AND p.TipoID = 2 

但我取回:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'i.MessageID = p.MessageID WHERE p.MessageID = 1 AND p.UserID = 1 AND p.TipoID = ' at line 3 

回答

1

试试这个:

SELECT i.*, p.* 
FROM Messaggi i 
INNER JOIN MessageMap p ON i.MessageID = p.MessageID 
WHERE i.MessageID = ? AND p.UserID = ? AND p.TipoID = ? 
+0

请参阅编辑页:(我有错误 – JackTurky

+0

@JackTurky,对不起,我忘了'ON',看我的编辑。它应该是'INNER JOIN MessageMap p ON i.MessageID = p .MessageID'而不是'INNER JOIN MessageMap p i.MessageID = p.MessageID'。 –

+0

好!!!这是我需要的!谢谢!:) – JackTurky

1

根据你的问题和疑问,简单的解决方案,我觉得可能是这个查询(也许还有另外的列那涉及您的表)

SELECT A.* 
FROM MessageMap A 
    INNER JOIN Message B on A.MessageId = B.MessageId 
WHERE 
    A.UserId = ? 
    AND A.TipoID = ? 
    AND A.MessageId = ? 

另外,请或指定,如果你需要的3个参数你可以不发送他们中的任何一个。

+0

可能只是'Messaggi *'是诚实的。 – MatBailie

+0

请参阅编辑页:(我有错误 – JackTurky