2015-03-31 47 views
2

我有CAMPUS_IDs(NY1,PA1,VA1)和CLASS_IDs(大约10个班级) 所以我必须创建一个表,其中有Campus_id和Class_id列,并在哪个校园中分配班级被教。问题在于所有校园都教授一些课程,其中一些课程仅在一个校园内教授。如何设计该表?我试图创建下面的表,但它很凌乱:寻找在哪里教授课程的校园

_____________________ 
| class_id |campus_id 
--------------------- 
| math101 | NY1 | 
--------------------- 
| pyt218 | PA1 | 
--------------------- 
| C767  | VA1 | 
--------------------- 
| pyt218 | PA1 | 
_____________________ 

并且具有class_id的campus_id是另一个表的外键。

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这对我来说看起来是正确的,是什么问题? – Bob 2015-03-31 01:14:21

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问题是math101例如可能会在NY1和PA1校区中教授。 – 2015-03-31 03:57:46

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这将是class_campus表中的两个条目。一个用于NY1的math101和一个用于PA1的math101。您将使表中的class_id和campus_id唯一。你目前的样本有两次与PA1连接的pyt218,我认为这不是有效的。如果是这样,请解释。 – Bob 2015-03-31 12:29:44

回答

1

所以你想列出所有的班级教学的校园?对于像

class_id | campus_id 
math101 | NY1, PA1 
pyt218 | PA1, VA1, NY1 
... 

的输出,你可以使用现有的wm_concat功能的Oracle 10g:

with d as (
    select 'NY1' as campus_id, 'math101' as class_id from dual union all 
    select 'PA1' as campus_id, 'math101' as class_id from dual union all 
    select 'VA1' as campus_id, 'pyt218' as class_id from dual union all 
    select 'PA1' as campus_id, 'pyt218' as class_id from dual union all 
    select 'PA1' as campus_id, 'class3' as class_id from dual union all 
    select 'VA1' as campus_id, 'class3' as class_id from dual union all 
    select 'VA1' as campus_id, 'math101' as class_id from dual union all 
    select 'NY1' as campus_id, 'class3' as class_id from dual 
) 
select class_id, wm_concat(campus_Id) 
From d 
group by class_id 

在Oracle 11.2,也可以用来产生相同结果的新功能“LISTAGG” :

with d as (
    select 'NY1' as campus_id, 'math101' as class_id from dual union all 
    ... 
) 
select class_id, listagg(campus_id, ',') within group (order by campus_id) 
From d 
group by class_id