计算基于结果/ ID为多个字段

Question

扩展该解决方案的最终结果：Calculate Final outcome based on Results/ID

使用相同的业务逻辑，我怎么能获得基于该LA场旁边Final Result另一Final Result 2基于Employment场？当涉及多个领域时，排名功能显然会有所不同。

表T1扩展：

+----------+-----------+-----------------+-----------------+ 
| PersonID | Date | Employment |  LA  | 
+----------+-----------+-----------------+-----------------+ 
|  1 | 2/28/2017 | Stayed the same | Improved  | 
|  1 | 4/21/2017 | Stayed the same | Stayed the same | 
|  1 | 5/18/2017 | Stayed the same | Improved  | 
|  2 | 3/7/2017 | Improved  | Stayed the same | 
|  2 | 4/1/2017 | Stayed the same | Stayed the same | 
|  2 | 6/1/2017 | Stayed the same | Improved  | 
|  3 | 3/28/2016 | Improved  | Improved  | 
|  3 | 5/4/2016 | Improved  | Improved  | 
|  3 | 4/19/2017 | Worsened  | Worsened  | 
|  4 | 5/19/2016 | Worsened  | Stayed the same | 
|  4 | 2/16/2017 | Improved  | Stayed the same | 
+----------+-----------+-----------------+-----------------+ 

所需的输出：

+----------+-----------------+-----------------+ 
| PersonID | Final Result | Final Result 2 | 
+----------+-----------------+-----------------+ 
|  1 | Stayed the same | Improved  | 
|  2 | Improved  | Improved  | 
|  3 | Worsened  | Worsened  | 
|  4 | Improved  | Stayed the same | 
+----------+-----------------+-----------------+ 

Answer 1

添加另一个RN应该工作

select t1.personid, t1.employment, t2.LA 
from (select t1.*, 
       row_number() over (partition by personid 
           order by (case when employment <> 'Stayed the same' then 1 else 2 end), 
              date desc 
           ) as seqnum 
     from t1 
     ) t1 
left join 
    (select t1.PersonID, t1.LA, 
       row_number() over (partition by personid 
           order by (case when LA <> 'Stayed the same' then 1 else 2 end), 
              date desc 
           ) as seqnum 
     from t1) t2 on t2.PersonID = t1.PersonID and t2.seqnum = 1 
where t1.seqnum = 1