2016-12-27 60 views
0

我正尝试使用REDX传奇实现Google OAuth 2。如何通过REDX传奇处理Google OAuth流程

我有我的传奇观察者监听GOOGLE_AUTH动作,然后执行googleLogin

function *watchGoogleAuth() { 
    yield *takeLatest(GOOGLE_AUTH, googleLogin) 
} 

function *googleLogin() { 
    const id_token = yield call(GoogleSignIn); 
    console.log(id_token); 
    const response = yield call(HttpHelper, 'google_token', 'POST', id_token, null); 
    console.log(response); 
} 

GoogleSignIn的实现是在apis.js

export function GoogleSignIn() { 
    const GoogleAuth = window.gapi.auth2.getAuthInstance(); 

    GoogleAuth.signIn({scope: 'profile email'}) 
     .then(
     (res) => { 
      const GoogleUser = GoogleAuth.currentUser.get(); 
      return { 
      id_token: GoogleUser.getAuthResponse().id_token 
      }; 
     }, 
     (err) => { 
      console.log(err) 
     } 
    ) 
} 

但传奇似乎并没有等待GoogleSignIn来完成。只要OAuth同意屏幕弹出,传奇继续执行console.log而不等待谷歌登录承诺返回实际数据。

有没有更好的方法来处理这种情况?谢谢!

+1

GoogleSignIn函数应该返回promise –

回答

1

要扩展@ HenrikR的答案,生成器不会等待,除非它收到承诺。

export const GoogleSignIn =() => { 
    const GoogleAuth = window.gapi.auth2.getAuthInstance(); 

    return new Promise((resolve, reject) => { 
    GoogleAuth.signIn({scope: 'profile email'}) 
     .then(
     (res) => { 
      const GoogleUser = GoogleAuth.currentUser.get(); 
      resolve(GoogleUser.getAuthResponse().id_token); 
     }, 
     (err) => { 
      reject(err) 
     } 
    ); 
    }); 
} 

因此,您应该将yield语句包装在try/catch中。简化且有些懒惰:

function *googleLogin() { 
    try { 
    const id_token = yield call(GoogleSignIn); 
    if (id_token) { /* Possibly with more checks and validations */ 
     console.log(id_token); 
     const response = yield call(HttpHelper, 'google_token', 'POST', id_token, null); 
     console.log(response); 
    } 
    } catch (e) { 
    console.log(e); 
    } 
}