如何通过服务处理通知？

Question

我想开发一个android服务，知道是否有任何通知，然后采取行动。我不知道如何管理通知。
我想知道通知如何工作，以及如何倾听他们。

Answer 1

如this answer中所述，您应该使用BroadcastReceiver捕获适当的意图并执行您的预期操作。

你提到的一个例子是，接收短信应触发LED指示灯。如前所述here，你应该注册你的 'SMSReceiver' 广播接收器，像这样：

// SMS Receiver 
<receiver android:name="com.myexample.receivers.SMSReceiver" > 
    <intent-filter> 
     <action android:name="android.provider.Telephony.SMS_RECEIVED" /> 
    </intent-filter> 
</receiver> 

...而有所界定，像这样的代码：

public class SMSReceiver extends BroadcastReceiver { 
private final String DEBUG_TAG = getClass().getSimpleName().toString(); 
private static final String ACTION_SMS_RECEIVED = "android.provider.Telephony.SMS_RECEIVED"; 
private Context mContext; 
private Intent mIntent; 

// Retrieve SMS 
public void onReceive(Context context, Intent intent) { 
    mContext = context; 
    mIntent = intent; 

    String action = intent.getAction(); 

    if(action.equals(ACTION_SMS_RECEIVED)){ 

     String address, str = ""; 
     int contactId = -1; 

     SmsMessage[] msgs = getMessagesFromIntent(mIntent); 

     // Iterate over the received messages with a loop, 
     // performing the desired actions during the process 
    } 

} 

public static SmsMessage[] getMessagesFromIntent(Intent intent) { 
    Object[] messages = (Object[]) intent.getSerializableExtra("pdus"); 
    byte[][] pduObjs = new byte[messages.length][]; 

    for (int i = 0; i < messages.length; i++) { 
     pduObjs[i] = (byte[]) messages[i]; 
    } 
    byte[][] pdus = new byte[pduObjs.length][]; 
    int pduCount = pdus.length; 
    SmsMessage[] msgs = new SmsMessage[pduCount]; 
    for (int i = 0; i < pduCount; i++) { 
     pdus[i] = pduObjs[i]; 
     msgs[i] = SmsMessage.createFromPdu(pdus[i]); 
    } 
    return msgs; 
} 

}

...作为LED的问题，大多数报道似乎粗略，但this answer有一个躲闪避难所变通办法：

android.provider.Settings.System.putInt(context.getContentResolver(), 
    "notification_light_pulse", on ? 1 : 0);