我构建了一个动态的breadcumb,它的某些部分是无效的url(不在urlpatterns中)。 我有这个templatetag: @register.filter
def crumbs(url):
"Return breadcrumb trail leading to URL for this page"
l = url.split('/')
urls = []
当我查询这个URL http://mywebsite.com/foos/
Django的给我: Page not found (404)
Request Method: GET
Request URL: http://mywebsite.com/foos//
The current URL, , didn't match any of these.
错误: - 在请求URL就加我