试图从PHP $conn = mysqli_connect($servername, $username, $password, $dbname);
// Find status for row with Username of the Url?username=
$sql = "SELECT Status FROM Users WHERE Username = '".$_GET["user
我正在读取.csv文件中的URL,我试图解析它们。为什么我只得到方案和netloc正确的价值观,当我把链接的功能urlparse(...)明确,见变量o2而不是当我给在urlparsenewsource? for line in file:
source = str(line.split(",")[2])
print("ORIGINAL URL: \n" + source)