随着org.apache.spark.mllib学习算法,我们用来设置管道没有训练算法 var stages: Array[org.apache.spark.ml.PipelineStage] = index_transformers :+ assembler
val pipeline = new Pipeline().setStages(stages)
然后经过我们二手LabeledPoi
例如我的情况类是 case class Test(id: String, myValues: List[Item])
case class Item(id: Long, order: Long)
,我得到这样 val checkValue: String = "id"
我想排序项测试的字符串值,我希望它看起来像 val test= Test("0", List(Item(0, 14),
里面我试图编译下面的代码: case class Settings(settingsList:List[Setting])
abstract class Setting[T](name:String, value:T)
但是编译器会抱怨: Error:(9, 54) class Setting takes type parameters
case class Settings(settin