我试图通过传递一个lambda函数作为第三个参数来调用QObject::connect
。作为QObject的第三个参数传递一个lambda函数时出错:: connect
不过,我视觉的Visual Studio给了我以下错误:
Unhandled exception at 0x0000000066B48265 (Qt5Cored.dll) in QCustomPlotInVS_FirstTry.exe: 0xC0000005: Access violation reading location 0x0000000000000008.
这里是关于调用堆栈的顶部3线时出现错误:
Qt5Cored.dll!QListData::size() Line 91
QCustomPlotInVS_FirstTry.exe!QList::size() Line 132 QCustomPlotInVS_FirstTry.exe!QCustomPlot::graph(int index) Line 9657
91号线在QList作。 h是: inline int size() const { return d->end - d->begin; }
我想我得到这个错误,因为我不正确地尝试使用一个指针(即QCustomPlot* plot
)无线一个lambda函数。
我的lambda函数的语法是否正确? 如果不是,我做错了什么?
这里是我称之为QObject::connect
与lambda函数功能:
void setupRealTimePlot(QCustomPlot* plot, QTimer* dataTimer)
{
plot->addGraph(); // blue line
plot->graph(0)->setPen(QPen(Qt::blue));
plot->graph(0)->setBrush(QBrush(QColor(240, 255, 200)));
plot->graph(0)->setAntialiasedFill(false);
plot->addGraph(); // red line
plot->graph(1)->setPen(QPen(Qt::red));
plot->graph(0)->setChannelFillGraph(plot->graph(1));
plot->addGraph(); // blue dot
plot->graph(2)->setPen(QPen(Qt::blue));
plot->graph(2)->setLineStyle(QCPGraph::lsNone);
plot->graph(2)->setScatterStyle(QCPScatterStyle::ssDisc);
plot->addGraph(); // red dot
plot->graph(3)->setPen(QPen(Qt::red));
plot->graph(3)->setLineStyle(QCPGraph::lsNone);
plot->graph(3)->setScatterStyle(QCPScatterStyle::ssDisc);
plot->xAxis->setTickLabelType(QCPAxis::ltDateTime);
plot->xAxis->setDateTimeFormat("hh:mm:ss");
plot->xAxis->setAutoTickStep(false);
plot->xAxis->setTickStep(2);
plot->axisRect()->setupFullAxesBox();
// make left and bottom axes transfer their ranges to right and top axes:
QObject::connect(plot->xAxis, SIGNAL(rangeChanged(QCPRange)), plot->xAxis2, SLOT(setRange(QCPRange)));
QObject::connect(plot->yAxis, SIGNAL(rangeChanged(QCPRange)), plot->yAxis2, SLOT(setRange(QCPRange)));
// setup a timer that repeatedly calls MainWindow::realtimeDataSlot:
QObject::connect(dataTimer, &QTimer::timeout,
[&]()
{
// calculate two new data points:
double key = QDateTime::currentDateTime().toMSecsSinceEpoch()/1000.0;
static double lastPointKey = 0;
if (key-lastPointKey > 0.01) // at most add point every 10 ms
{
double value0 = qSin(key); //qSin(key*1.6+qCos(key*1.7)*2)*10 + qSin(key*1.2+0.56)*20 + 26;
double value1 = qCos(key); //qSin(key*1.3+qCos(key*1.2)*1.2)*7 + qSin(key*0.9+0.26)*24 + 26;
// add data to lines:
plot->graph(0)->addData(key, value0);
plot->graph(1)->addData(key, value1);
// set data of dots:
plot->graph(2)->clearData();
plot->graph(2)->addData(key, value0);
plot->graph(3)->clearData();
plot->graph(3)->addData(key, value1);
// remove data of lines that's outside visible range:
plot->graph(0)->removeDataBefore(key-8);
plot->graph(1)->removeDataBefore(key-8);
// rescale value (vertical) axis to fit the current data:
plot->graph(0)->rescaleValueAxis();
plot->graph(1)->rescaleValueAxis(true);
lastPointKey = key;
}
// make key axis range scroll with the data (at a constant range size of 8):
plot->xAxis->setRange(key+0.25, 8, Qt::AlignRight);
plot->replot();
// calculate frames per second:
static double lastFpsKey;
static int frameCount;
++frameCount;
if (key-lastFpsKey > 2) // average fps over 2 seconds
{
lastFpsKey = key;
frameCount = 0;
}
});
dataTimer->start(0); // Interval 0 means to refresh as fast as possible
}
你的回答是正确的。我将'[&](){// ...}'改为'[=](){// ...}'并且它工作正常。但是,我不清楚为什么。我想如果我通过价值捕获它会创建一个变量的副本(在我的例子中是'QCustomPlot * plot'),那么对副本的任何更改都不适用于原始变量。我想我只是意识到我的担忧是错误的,因为复制一个指针会给出一个新的变量,它仍然指向我想修改的对象。我的解释看起来是否正确? – user3731622
没错。您可以更容易地将引用解析为指针:通过引用捕获本地指针变量就像将指针存储在双指针内部一样。当以后你尝试使用它时,它指向一个不再存在的局部变量。相反,通过值捕获它就像创建一个指向原始对象的新QCustomPlot *(指针的值是指向对象的地址)。 –