2017-02-04 129 views
1

帮助。我怎么能移动或从一个表中移动一行到另一个mysql表中?一旦我点击“批准”,选定的行将转移到数据库中的另一个表格。请检查我的代码。谢谢!如何将一行从一个表移动到另一个表中的mysql?

message.php

<?php 


include('connect.php'); 
$result = mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM message"); 
while($row = mysqli_fetch_array($result)) 
{ 
    echo '<tr class="record">'; 
    echo '<td style="background-color: #F8F8F8 ;font-size: 13px; color: maroon; 
     font-weight: bold; border-left: 1px solid #C1DAD7;">'.$row['name'].'</td>'; 
    echo '<td><div style="font-size: 13px;" align="left">'.$row['address'].'</div></td>'; 
    echo '<td><div style="color:maroon; font-size: 13px;"align="left">Email:<br></div> 
     <div style="font-size: 13px;"align="left">'.$row['email'].'</div><br> 
     <div style="font-size: 13px; color:maroon;"align="left">Contact No.<br></div> 
     <div style="font-size: 13px;"align="left">'.$row['number'].'</div></td>'; 
    echo '<td><div style="font-size: 13px;"align="left">'.$row['services'].'</div></td>'; 
    echo '<td><div style="color:maroon; font-size: 13px;"align="left">Desired Date:<br></div> 
     <div style="font-size: 13px;"align="left">'.$row['shootdate'].'</div><br> 
     <div style="font-size: 13px; color:maroon;"align="left">Desired Time: <br></div> 
     <div style="font-size: 13px;"align="left">'.$row['shoottime'].'</div></td>'; 
    echo '<td><div style="font-size: 13px;"align="left">'.$row['place'].'</div></td>'; 
    echo '<td><div style="font-size: 13px;"align="left">'.$row['message'].'</div></td>'; 
    echo '<td><div align="center"> 
     <a href="acceptmessage.php" id="'.$row['message_id'].'" class="acceptbutton" 
      title="Click To Approve">Approve</a><br><br> 
     <a href="deletemessage.php" id="'.$row['message_id'].'" class="delbutton" 
      title="Click To Decline" style="color:red;">Decline</a></div></td>'; 
    echo '</tr>'; 
    } 
?> 

acceptmessage.php

<?php 
    include('../db.php'); 
    if($_GET['id']){ 
    $id = (isset($_GET['id']) ? $_GET['id'] : null); 
    $sql = "INSERT INTO accept (name, address, email, number, services, shootdate, shoottime, place) SELECT name, address, email, number, services, shootdate, shoottime, place FROM message WHERE message_id='$id'"; 
    mysqli_query($GLOBALS["___mysqli_ston"], $sql);} 
?> 
+2

你有错误? .. – scaisEdge

回答

1

如果列MESSAGE_ID是int我想你应该删除$ ID的单引号是这样的:

$sql = "INSERT INTO accept (name, address, email, number, services, shootdate, shoottime, place) SELECT name, address, email, number, services, shootdate, shoottime, place FROM message WHERE message_id=$id"; 

P.S.您应该在查询中使用准备好的语句,而不是直接插入变量,这样可以避免SQL注入。

事情是这样的:

$sql = "INSERT INTO accept (name, address, email, number, services, shootdate, shoottime, place) SELECT name, address, email, number, services, shootdate, shoottime, place FROM message WHERE message_id=?"; 
$stmt = $connection->prepare($sql); 
$stmt->bindValue(1, $id); 
$stmt->execute();