我自从算出来并决定回答我自己的问题h只是为了那些处于类似情况的人的利益。
每当我想给任何字符串,我用我创造了这个辅助函数:
- (void) send:(NSString *)string {
const uint8_t *message = (const uint8_t *)[string UTF8String];
if (_outStream && [_outStream hasSpaceAvailable])
if([_outStream write:message maxLength:strlen((char *)message)] == -1)
NSLog(@"Failed sending data to peer");
}
在接收端,它看起来像这样:
- (void) stream:(NSStream *)stream handleEvent:(NSStreamEvent)eventCode {
switch(eventCode) {
case NSStreamEventHasBytesAvailable:
{
if (stream == _inStream) {
// read it in
unsigned int len = 0;
len = [_inStream read:buf maxLength:buffSize];
buf[len] = '\0';
if(!len) {
if ([stream streamStatus] != NSStreamStatusAtEnd)
NSLog(@"Failed reading data from peer");
} else {
NSString *message = [NSString stringWithUTF8String:(char *)buf];
// here you do whatever you need with your received NSString *message
}
}
}
}
缓冲区定义为:
#define buffSize 60000
uint8_t buf[buffSize];
60,000是相当随意的,你可以改变它以适应你的需求。
关于上述的几点说明。尽管为这些字符串设置相当大的缓冲区是安全的,但您绝对不能保证一次接收字符串。在实际的应用程序中,您应该仔细设计一个可以依赖的特定协议,以检查是否收到了整个字符串,并在后续NSStreamEvent
s中收到字符串(如有必要)。
我应该只是通过类似 (const uint8_t *)[strBuffer UTF8String]; 其中strBuffer是缓冲区写入的NSString? – SaltyNuts 2010-06-21 20:10:56