我使用onmouseover和onmouseout来查看图像,但它不能在chrome中工作。需要解决这个问题。所有功能,事件等的浏览器兼容性代码
脚本
<script>
var img;
window.onload = function() {
img = document.getElementById ("img");
}
</script>
<img style= "position:absolute;TOP:90px; LEFT:185px;visibility:hidden;"
class="two"
id="img"
src="services/web2.png"
width="800" height="500" alt=""/>
<div class="item home">
<img src="imagess/bg_home.png" alt="" width="199" height="199" class="circle"/>
<a href="#" class="icon"></a>
<h2>IT</h2>
<ul>
<li>
<a href="target4"
onMouseOver="img.style.visibility='visible'; img.src='services/web2.png'"
onMouseOut="img.style.visibility='hidden';">Sales & Service</a>
</li>
<li>
<a href="target5"
onMouseOver="img.style.visibility='visible'; img.src='services/web2.png'"
onMouseOut="img.style.visibility='hidden';">CCTV</a>
</li>
<li>
<a href="target6"
onMouseOver="img.style.visibility='visible'; img.src='services/web2.png'"
onMouseOut="img.style.visibility='hidden';">DVR</a>
</li>
</ul>
</div>
为什么你标记你的问题“jQuery”? – Bergi
错误控制台在Chrome中说什么? – aorcsik
@fork:是的,这就是我问过的原因。 OP是否包含它但不使用它?或者他想使用但不知道如何? – Bergi