2017-09-27 48 views
-5

我想问一下我面临的逻辑错误?即使我进入1号为每种类型的光盘,输出将有5%的折扣。5%的优惠只适用于2〜5购买CD的C++ if else逻辑错误和不正确的输出

#include <iostream> 
using namespace std; 

int main() { 
    int type_i,type_l,type_o,type_c; 
    float cost_i,cost_l,cost_o,cost_c,discount_i,discount_l,discount_o,discount_c,discounted_i,discounted_l,discounted_o,discounted_c,total_dis,amount; 
    float price_i=39.9,price_l=29.9,price_o=49.9,price_c=59.9; 

    cout<<"\t\t\tPower House\n"; 
    cout<<"Quantity of International CD:"; 
    cin>>type_i; 
    cout<<"Quantity of Local CD:"; 
    cin>>type_l; 
    cout<<"Quantity of Oldies CD:"; 
    cin>>type_o; 
    cout<<"Quantity of Classic CD:"; 
    cin>>type_c; 

    cost_i=type_i*price_i; 
    cost_l=type_l*price_l; 
    cost_o=type_o*price_o; 
    cost_c=type_c*price_c; 

    if (2<=type_i<=5){ 

     discount_i=cost_i*0.05; 
     discounted_i=cost_i*0.95; 
     } 
     else if(6<=type_i<=10){ 

      discount_i=cost_i*0.1; 
      discounted_i=cost_i*0.9; 
     } 
     else if(11<=type_i<=15){ 

      discount_i=cost_i*0.15; 
      discounted_i=cost_i*0.85; 
     } 
     else if(16<=type_i<=20){ 

      discount_i=cost_i*0.2; 
      discounted_i=cost_i*0.8; 
     } 
     else if(type_i>20){ 

      discount_i=cost_i*0.25; 
      discounted_i=cost_i*0.75; 
     } 
     else if(0<=type_i<=1){ 
     discounted_i=cost_i; 
    } 
    if (2<=type_l<=5){ 

     discount_l=cost_l*0.05; 
     discounted_l=cost_l*0.95; 
     } 
     else if(6<=type_l<=10){ 

      discount_l=cost_l*0.1; 
      discounted_l=cost_l*0.9; 
     } 
     else if(11<=type_l<=15){ 

      discount_l=cost_l*0.15; 
      discounted_l=cost_l*0.85; 
     } 
     else if(16<=type_l<=20){ 

      discount_l=cost_l*0.2; 
      discounted_l=cost_l*0.8; 
     } 
     else if(type_l>20){ 

      discount_l=cost_l*0.25; 
      discounted_l=cost_l*0.75; 
     } 
     else if(0<=type_l<=1){ 
     discounted_l=cost_l; 
    } 
    if (2<=type_o<=5){ 

     discount_o=cost_o*0.05; 
     discounted_o=cost_o*0.95; 
     } 
     else if(6<=type_o<=10){ 

      discount_o=cost_o*0.1; 
      discounted_o=cost_o*0.9; 
     } 
     else if(11<=type_o<=15){ 

      discount_o=cost_o*0.15; 
      discounted_o=cost_o*0.85; 
     } 
     else if(16<=type_o<=20){ 

      discount_o=cost_o*0.2; 
      discounted_o=cost_o*0.8; 
     } 
     else if(type_o>20){ 

      discount_o=cost_o*0.25; 
      discounted_o=cost_o*0.75; 
     } 
     else if (0<=type_o<=1){ 
     discounted_o=cost_o; 
    } 
    if (2<=type_c<=5){ 

     discount_c=cost_c*0.05; 
     discounted_c=cost_c*0.95; 
     } 
     else if(6<=type_c<=10){ 

      discount_c=cost_c*0.1; 
      discounted_c=cost_c*0.9; 
     } 
     else if(11<=type_c<=15){ 

      discount_c=cost_c*0.15; 
      discounted_c=cost_c*0.85; 
     } 
     else if(16<=type_c<=20){ 

      discount_c=cost_c*0.2; 
      discounted_c=cost_c*0.8; 
     } 
     else if(type_c>20){ 

      discount_c=cost_c*0.25; 
      discounted_c=cost_c*0.75; 
     } 
     else if(0<=type_c<=1){ 
     discounted_c=cost_c; 
    } 

    total_dis=discount_i+discount_l+discount_o+discount_c; 
    amount=discounted_i+discounted_l+discounted_o+discounted_c; 

    cout<<"Total discount:"<<total_dis; 
    cout<<"\nAmount due:"<<amount; 


} 

https://i.stack.imgur.com/qEPgK.png

^以上是我的问题对于这个程序

+1

'2 <= type_i <= 5'总是'true',因为它与'(2 <= type_i)<= 5'相同,与'(true)<= 5'是一样的TRUE;。 – user463035818

+2

你需要检查两个条件'2 <= type_i和type_i <= 5' – user463035818

+0

与问题本身并不完全相关。但对于这样的问题,我会构建一个CD类 – quantik

回答

1

你需要写这些条件,(11<=type_c<=15)作为(11<=type_c && type_c<=15)