Php到Android获取返回值

我有一个基本的身份验证表格现在工作。现在它只是在登录成功时发送一个字符串“成功”，不成功时发送“假”。当它成功时，我想返回用户数据，如UserID用于其他目的。我怎样才能做到这一点？这里是我的PHP代码：Php到Android获取返回值

static public function Login($LoginID, $pass) { 
       $result = Db::getInstance()->getRow(' 
       SELECT `UserID` 
       FROM `'._DB_PREFIX_.'cman_users` 
       WHERE `LoginID` = '.$LoginID.' 
       AND `password` = \''.$pass.'\' 
       '); 
//echo "User:Login ($LoginID)<br>"; 
       if(isset($result['UserID']) && $result['UserID'] > 0) 
         return $result['UserID']; 

       else return 0; 
     }

这里是我的Android代码：

httpclient=new DefaultHttpClient(); 
      // httppost= new HttpPost("http://127.0.0.1/API/check.php"); // make sure the url is correct. 
      //add your data 
      //httppost= new HttpPost("http://10.0.2.2:8080/API/check.php"); 
      httppost = new HttpPost("http://cman.avaninfotech.com/api/cman/v1/checkLogin/"); 
      nameValuePairs = new ArrayList<>(2); 

      nameValuePairs.add(new BasicNameValuePair("loginID",loginID.getText().toString().trim())); // $Edittext_value = $_POST['Edittext_value']; 
      nameValuePairs.add(new BasicNameValuePair("loginPass",loginPass.getText().toString().trim())); 
      httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
      //Execute HTTP Post Request 
      response=httpclient.execute(httppost); 

      ResponseHandler<String> responseHandler = new BasicResponseHandler(); 
      final String response = httpclient.execute(httppost, responseHandler); 
      System.out.println("Response : " + response); 
      runOnUiThread(new Runnable() { 
       public void run() { 
        // tv.setText("Response from PHP : " + response); 
        dialog.dismiss(); 
       } 
      }); 

      if(response.equalsIgnoreCase("1")){ 
       runOnUiThread(new Runnable() { 
        public void run() { 
         Toast.makeText(MainActivity.this, "Login Success", Toast.LENGTH_SHORT).show(); 
        } 
       }); 

       startActivity(new Intent(MainActivity.this, HomePage.class)); 
      }else{ 
       showAlert(); 
      } 

     } catch (ClientProtocolException e) { 
      e.printStackTrace(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
    }

来源

2015-02-23 John Simon

可能这会帮助你，你会得到响应为JSON编码字符串。对不起，我不知道android代码。

static public function Login($LoginID, $pass) { 
        $result = Db::getInstance()->getRow(' 
        SELECT `UserID` 
        FROM `'._DB_PREFIX_.'cman_users` 
        WHERE `LoginID` = '.$LoginID.' 
        AND `password` = \''.$pass.'\' 
        '); 
    //echo "User:Login ($LoginID)<br>"; 
        if(isset($result['UserID']) && $result['UserID'] > 0) 
          echo json_encode($result['UserID']); 
        else 
         echo json_encode('0'); 
      }

来源

2015-02-23 09:34:26 Elby

我想回到像用户ID的用户信息用于其他目的

既从PHP脚本返回状态和用户ID。使用json_encode创建一个json对象。做以下：

1.创建并从PHP返回的JSON对象：

class LoginDetails { 
     public $LoginID = ""; 
     public $status = ""; 

    } 
$obj = new LoginDetails(); 
$obj->LoginID = $LoginID; 
if(isset($result['UserID']) && $result['UserID'] > 0) 
    $obj->status = "1"; 
    else 
    $obj->status = "0"; 

return json_encode($obj);

2.解析字符串从服务器recived在JSON对象：

JSONObject jsonObject=new JSONObject(response); 
    String strLoginID=jsonObject.optString("LoginID"); 
    int status=jsonObject.optInt("status");

来源

2015-02-23 09:46:02

Php到Android获取返回值

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