0
我在解决这个问题时遇到了困难,我无法找到正确的答案来解决我遇到的问题。我希望一个场景/舞台被用作按钮来打开另一个场景/舞台,并且这两个都是用同样的方法调用的。下面是完整的方法:使用场景/舞台作为按钮来打开另一个场景/舞台
public void createChatWindowMinimized(int agentKey, String message)
{
LOGGER.enterMethod();
try{
ChatAgentsController chatController = null;
User agent = getModel().getRealtimeAgentNode().getUser(agentKey);
String firstNameLastName = agent.getFirstname() + " " + agent.getLastName();
UserAvatar userAvatar = getModel().getRealtimeAgentNode().getUserAvatar(agentKey);
ImageView agentAvatar;
agentAvatar = new ImageView();
Stage toastStage = new Stage();
toastStage.initStyle(StageStyle.UNDECORATED);
toastStage.setHeight(120);
toastStage.setWidth(250);
BorderPane toastBorderPane = new BorderPane();
Scene toastScene = new Scene(toastBorderPane);
toastScene.getStylesheets().add(this.getClass().getResource("MessageToaster.css").toExternalForm());
if(userAvatar == null || userAvatar.getBuffer() == null)
agentAvatar.getStyleClass().add("AgentDefaultAvatar");
else
agentAvatar.setImage(new Image(new ByteArrayInputStream(userAvatar.getBuffer()), 48, 48, true, true));
VBox vboxToastImage = new VBox();
vboxToastImage.getStyleClass().add("ToasterImage");
ImageView imgToastAgent = agentAvatar;
imgToastAgent.setFitHeight(60);
imgToastAgent.setFitWidth(60);
vboxToastImage.getChildren().add(imgToastAgent);
toastBorderPane.setLeft(vboxToastImage);
VBox vboxInCenter = new VBox();
Label userName = new Label(firstNameLastName);
userName.getStyleClass().add("ToasterUserName");
Text toasterContent = new Text(message);
toasterContent.getStyleClass().add("ToasterMessage");
vboxInCenter.getChildren().addAll(userName, toasterContent);
vboxInCenter.getStyleClass().add("ToasterBox");
toastBorderPane.setCenter(vboxInCenter);
toastBorderPane.getStyleClass().add("ToasterBorderPane");
Rectangle2D primaryScreenBounds = Screen.getPrimary().getVisualBounds();
toastStage.setX(primaryScreenBounds.getMinX() + primaryScreenBounds.getWidth() - TOASTER_WINDOW_WIDTH);
toastStage.setY(primaryScreenBounds.getMinY() + primaryScreenBounds.getHeight() - TOASTER_WINDOW_HEIGHT);
toastStage.setScene(toastScene);
// check if a chat window for this user already exists
if (chatAgentsMap.containsKey(agentKey))
{
// chat window has been created
chatController = chatAgentsMap.get(agentKey);
LOGGER.message(String.format("Showing chat window for agent '%d'.", agentKey));
if(!chatController.getChatStage().isFocused()){
toastStage.show();
chatController.getChatStage().show();
}
}
else
{
// create new chat window
LOGGER.message(String.format("Creating chat window for agent '%d'.", agentKey));
chatController = ChatAgentsController.create(this, agentKey, connectedToOpenfireServer, true);
toastStage.show();
toastStage.setAlwaysOnTop(true);
//-----Here is where I want that the toastStage or the toastScene is clickable by mouse and that it opens the window already created chatController
chatController.getChatStage().show();
chatAgentsMap.put(agentKey, chatController);
}
if (chatController != null && message != null) // append received message to the chat text area
chatController.addChatEntry(agentKey, message);
}
catch (Throwable t)
{
LOGGER.error(t);
}
finally
{
LOGGER.leaveMethod();
}
}
我一直试图用从点击鼠标事件,但我不工作,因为我的变量,实例化其他窗口(chatController.getChatStage()显示()。)不最后。第一if
语句之前
// ChatAgentsController chatController = null;
,并宣布,一旦初始化,:
这里: ChatAgentsController chatController = chatAgentsMap.computeIfAbsent(agentKey中,k - > { LOGGER.message(的String.format(“创建聊天窗口代理'%d'。“,k)); return ChatAgentsController.create(this,k,connectedToOpenfireServer,true); }); 它要求尝试抓住,但是当我这样做时,它仍然显示一些错误。其中之一就是lambda表达式中的错误返回类型。 –
所以'ChatAgentsController.create(...)'声明一个检查的异常?在'try'中包装'return'语句并使相应的'catch'块记录异常并返回'null'应该可以工作(尽管不一定是最好的)。 –
它非常完美,非常感谢!你会介意评价这个问题吗?毕竟,我还没有看到过很多这样的问题,而且我知道很多其他人可能会觉得它很有用。 –