2016-09-06 68 views
2

我尝试这样做:日期范围问题

pd.date_range(2000, periods = 365, freq = 'D',format = '%d-%m-%Y') 

为什么我得到这样的结果:

DatetimeIndex(['1970-01-01 00:00:00.000002', '1970-01-02 00:00:00.000002', 
       '1970-01-03 00:00:00.000002', '1970-01-04 00:00:00.000002', 
       '1970-01-05 00:00:00.000002', '1970-01-06 00:00:00.000002', 
       '1970-01-07 00:00:00.000002', '1970-01-08 00:00:00.000002', 

任何帮助吗?

回答

2

您需要添加''2000

print (pd.date_range('2000', periods = 365, freq = 'D')) 

DatetimeIndex(['2000-01-01', '2000-01-02', '2000-01-03', '2000-01-04', 
       '2000-01-05', '2000-01-06', '2000-01-07', '2000-01-08', 
       '2000-01-09', '2000-01-10', 
       ... 
       '2000-12-21', '2000-12-22', '2000-12-23', '2000-12-24', 
       '2000-12-25', '2000-12-26', '2000-12-27', '2000-12-28', 
       '2000-12-29', '2000-12-30'], 
       dtype='datetime64[ns]', length=365, freq='D') 

如果使用int,将其转换为str

print (pd.date_range(str(2000), periods = 365, freq = 'D')) 
1

试试这个

pd.date_range('1/1/2000', periods = 365, freq = 'D',format = '%d-%m-%Y') 
+0

是可能的,如果生成DATE_RANGE我们只提供2000而不是1/1/2000? – bikuser