map and filter with lodash 3.10.1

Question

我需要返回对象数组的属性label，其中属性visible与false不同。

例如：

{ 
    "EMPRESA": "CMIP", 
    "CD_MAQ": "EXE03", 
    "DT_INI_MAQ": "1900-01-01", 
    "DSP_MAQ": "EXE03", 
    "DSR_MAQ": "EXE03", 
    "RACIO_PARAGEM": null, 
    "ID_MAGNITUDE": "101", 
    "DT_INI_DM": "1900-01-01", 
    "DT_FIM": null, 
    "DT_RowId": "row_CMIPEXE031900-01-01", 
    "DESIGEMPRESA": "CMIP", 
    "DSP_MAGNITUDE": "Metros" 
} 

和对象的数组：

var tableColumns= [ 
      { 
       "targets": 0, 
       "title": "", //Datatables 
       "label": "", //Editor 
       "data": 'EMPRESA', 
       "name": 'EMPRESA', 
       "width": "", 
       "type": "hidden", //Editor 
       "visible": false, //DataTables 
       "defaultContent": "", 
       "bSearchable": false, 
       "orderable": false 
      }, {.... 

我设置一个小提琴。提前致谢。

Answer 1

我需要返回对象的数组，其中属性附加伤害visible是从false diferent的属性附加伤害label。

const data = [ 
 
    { label: 'A', visible: false }, 
 
    { label: 'B', visible: true }, 
 
    { label: 'C', visible: true }, 
 
    { label: 'D', visible: false }, 
 
    { label: 'E', visible: true } 
 
] 
 

 
const result = 
 
    data 
 
    .filter(x => x.visible !== false) 
 
    .map(x => x.label) 
 
    
 
console.log(result) 
 
// [ 'B', 'C', 'E' ]

---

通过数据多次上述迭代。如果你想避免这种情况，可以转导

const data = [ 
 
    { label: 'A', visible: false }, 
 
    { label: 'B', visible: true }, 
 
    { label: 'C', visible: true }, 
 
    { label: 'D', visible: false }, 
 
    { label: 'E', visible: true } 
 
] 
 

 
const mapper = f => 
 
    k => (acc, x) => k (acc, f (x)) 
 
    
 
const filterer = p => 
 
    k => (acc, x) => p (x) ? k (acc, x) : acc 
 
    
 
const tcomp = (tf, tg) => 
 
    k => tf (tg (k)) 
 
    
 
const concat = (xs, ys) => 
 
    xs.concat(ys) 
 
    
 
const transduce = (...ts) => xs => 
 
    xs.reduce (ts.reduce (tcomp, k => k) (concat), []) 
 
    
 
const visibleLabels = 
 
    transduce (filterer (x => x.visible !== false), 
 
      mapper (x => x.label)) 
 
      
 
console.log (visibleLabels (data)) 
 
// [ 'B', 'C', 'E' ]